Answer:
Freeze wedging is caused by the repeated freeze-thaw. Frost wedging occurs as the result of 9% expansion of water when it is converted to ice. Cracks filled with water are forced further apart when it freezes.
Answer:
0.36 M
Explanation:
There is some info missing. I think this is the complete question.
<em>Suppose a 250 mL flask is filled with 0.30 mol of N₂ and 0.70 mol of NO. The following reaction becomes possible:
</em>
<em>N₂(g) +O₂(g) ⇄ 2 NO(g)
</em>
<em>The equilibrium constant K for this reaction is 7.70 at the temperature of the flask. Calculate the equilibrium molarity of O₂. Round your answer to two decimal places.</em>
<em />
Initially, there is no O₂, so the reaction can only proceed to the left to attain equilibrium. The initial concentrations of the other substances are:
[N₂] = 0.30 mol / 0.250 L = 1.2 M
[NO] = 0.70 mol / 0.250 L = 2.8 M
We can find the concentrations at equilibrium using an ICE Chart. We recognize 3 stages (Initial, Change, and Equilibrium) and complete each row with the concentration or change in the concentration.
N₂(g) +O₂(g) ⇄ 2 NO(g)
I 1.2 0 2.8
C +x +x -2x
E 1.2+x x 2.8 - 2x
The equilibrium constant (K) is:
![K=7.70=\frac{[NO]^{2}}{[N_{2}][O_{2}]} =\frac{(2.8-2x)^{2} }{(1.2+x).x}](https://tex.z-dn.net/?f=K%3D7.70%3D%5Cfrac%7B%5BNO%5D%5E%7B2%7D%7D%7B%5BN_%7B2%7D%5D%5BO_%7B2%7D%5D%7D%20%3D%5Cfrac%7B%282.8-2x%29%5E%7B2%7D%20%7D%7B%281.2%2Bx%29.x%7D)
Solving for x, the positive one is x = 0.3601 M
[O₂] = 0.3601 M ≈ 0.36 M
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Answer:
Your answer would be a). 2.0 × 10-9
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Work:
In your question the "ph" of a 0.55 m aqueous solution of hypobromous acid temperature is at 25 degrees C, and it's "ph" is 4.48.
You would use the ph (4.48) to find the ka for "hbro"
[H+]
=
10^-4.48
=
3.31 x 10^-5 M
=
[BrO-]
or: [H+] = 10^-4.48 = 3.31 x 10^-5 M = [BrO-]
Then you would find ka:
(3.31 x 10^-5)^2/0.55 =2 x 10^-9
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<em>-Julie</em>
If 0.380 mol of barium nitrate is allowed to react with an excess of phosphoric acid, 0.127 moles of barium phosphate could be formed.
<h3>How to calculate number of moles?</h3>
The number of moles of a compound can be calculated stoichiometrically as follows:
Based on this question, the following chemical equation is given:
Ba (NO3)2+ H3PO4 → Ba3(PO4)2+ HNO3
The balanced equation is as follows:
3Ba(NO3)2 + 2H3PO4 → Ba3(PO4)2 + 6HNO3
3 moles of barium nitrate produces 1 mole of barium phosphate
Therefore, 0.380 moles of barium nitrate will produce 0.380/3 = 0.127moles of barium phosphate.
Learn more about stoichiometry at: brainly.com/question/9743981
Yes,covalent bonds do dissolve in methanol
