Problem One
You will use both m * c * deltaT and H = m * heat of fusion.
Givens
m = 12.4 grams
c = 0.1291
t1 = 26oC
t2 = 1204
heat of fusion (H_f) = 63.5 J/grams.
Equation
H = m * c * deltaT + m * H_f
Solution
H = 12.4 * 0.1291 * (1063 - 26) + 12.4 * 63.5
H = 1660.1 + 787.4
H = 2447.5 or 2447.47 is the exact answer. I have to leave the rounding to you. I have no idea where to round it although I suspect 2450 would be right for 3 sig digs.
Problem Two
Formula and Givens
t1 = 14.5
t2 = 50.0
E = 5680
c = 4.186
m = ??
E = m c * deltaT
Solution
5680 = m * 4.186 * (50 - 14.5)
5680 = m * 4.186 * (35.5)
5680 = m * 148.603 * m
m = 5680 / 148.603
m = 38.22 grams That isn't very much. Be very sure you are working in joules. You'd leave that many grams in the kettle after drying it thoroughly.
m = 38.2 to 3 sig digs.
<span>It affects only one chemical reaction</span>
Answer:
63.01284 g/mol
Explanation:
This compound is also known as Nitric Acid.
Convert grams HNO3 to moles or moles HNO3 to grams
Molecular weight calculation:
1.00794 + 14.0067 + 15.9994*3
Percent composition by element
Element Symbol Atomic Mass # of Atoms Mass Percent
Hydrogen H 1.00794 1 1.600%
Nitrogen N 14.0067 1 22.228%
Oxygen O 15.9994 3 76.172%
Answer:
aluminum will lose 3 electrons.
Explanation:
to be stable and losing 3 is easier than gaining 5.
anddd its a metal. :)
Answer: A
Explanation: because It shows how they mark there territory by unreining
