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Dennis_Churaev [7]
4 years ago
12

Explain why the first ionization energy K is less than that of Ca

Chemistry
1 answer:
Ainat [17]4 years ago
5 0

Answer:

The first ionization energy for K is less than Ca because Ca has a larger effective nuclear charge.

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Lithium hydroxide reacts with hydrobromic acid(HBr) to produce lithium bromide and water. If you
sweet-ann [11.9K]

Answer:

3.00 moles of Lithium bromide will be produced

Explanation:

The reaction that takes place is:

  • LiOH + HBr → LiBr + H₂O

By looking at the reaction equation, we can see that<em> the reaction of 1 mol of lithium hydroxide (LiOH) produces 1 mol of lithium bromide (LiBr).</em> Thus, 3.00 moles of LiOH would conversely produce 3.00 moles of LiBr.

4 0
3 years ago
What does it mean if a solution is a "weak acid "? Strong acid? Give logical ph values for each
galina1969 [7]

Answer:

A weak acid is an acid that partially dissociates into its ions in an aqueous solution or water. In contrast, a strong acid fully dissociates into its ions in water. At the same concentration, weak acids have a higher pH value than strong acids.

Explanation:

:)

5 0
3 years ago
What is the partial pressure of argon, par, in the flask? express your answer to three significant figures and include the appro
monitta
Given which are missing in your question:
the flask is filled with 1.45 g of argon at 25 C° 
So according to this formula (Partial pressure):
PV= nRT
first, we need n, and we can get by substitution by:
n =  1.45/mass weight of argon
   = 1.45 / 39.948 = 0.0363 mol of Ar
we have R constant = 0.0821
and T in kelvin = 25 + 273 = 298
and V = 1 L
∴ P * 1 = 0.0363* 0.0821 * 298 = 0.888 atm

3 0
3 years ago
Which of the atoms below are least likely to violate the octet rule?
Levart [38]

Answer:

F i think i pretty sure F!!!!!!!!

5 0
3 years ago
2. A block of aluminum with a mass of 140g is cooled from 98.4oC to 62.2oC with a release of 1137J of heat. From these data, cal
NeTakaya
Q =  M * C *ΔT

Q / <span>ΔT  = M

</span>Δf - Δi =  98.4ºC - 62.2ºC = 36.2ºC
<span>
C = 1137 J / 140 * 36.2

C = 1137 / 5068

C = 0.224 J/gºC</span>
8 0
3 years ago
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