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4 years ago

Which profession is likely to use a radiation shield

Chemistry

2 answers:

Anna35 [415]4 years ago

5 0

The correct answer would be, A Dentist.

zhannawk [14.2K]4 years ago

4 0

it is D geologist....................

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I put 40 points on this!!! PLEASE HELP!! I NEED AN A OR MY MOM IS GONNA KILL ME!

pshichka [43]

Hi there!

For one and two, I could not find anything. I highly suggest you talk to your textiles teacher for both one, two, and five, and review the whole assignment with them.

3.)- Lifting and shifting the iron to produce more steam and less wrinkles on a garment

4.) Using the "wrong" side of the garment to make it more rigid

5.) Seam along the interface

6.) Before one puts a new garment for the first time in the laundry.

6 0

3 years ago

The percentage composition of acetic acid is found to be 39.9% C, 6.7% H, and 53.4% O. What is the empirical formula of acetic a

anastassius [24]

Answer:

CH₂O

Explanation:

From the question given above, the following data were obtained:

Carbon (C) = 39.9%

Hydrogen (H) = 6.7%

Oxygen (O) = 53.4%

Empirical formula =?

The empirical formula of acetic acid can be obtained as follow:

C = 39.9%

H = 6.7%

O = 53.4%

Divide by their molar mass

C = 39.9 / 12 = 3.3

H = 6.7 / 1 = 6.7

O = 53.4 / 16 = 3.3

Divide by the smallest

C = 3.3 / 3.3 = 1

H = 6.7 / 3.3 = 2

O = 3.3 / 3.3 = 1

The empirical formula => CH₂O

4 0

3 years ago

The mole fraction of CO2 in a certain solution with H2O as the solvent is 3.6 × 10−4. What is the approximate molality of CO2 in

nataly862011 [7]

Answer: C) 0.020 m

Explanation:

Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

$Molality=\frac{n\times 1000}{W_s}$

where,

n = moles of solute

$W_s$ = weight of solvent in g

Mole fraction of $CO_2$ is = $3.6\times 10^{-4}$ i.e. $3.6\times 10^{-4}$ moles of $CO_2$ is present in 1 mole of solution.

Moles of solute $(CO_2)$ = $3.6\times 10^{-4}$

moles of solvent (water) = 1 - $3.6\times 10^{-4}$ = 0.99

weight of solvent = $moles\times {\text {Molar mass}}=0.99\times 18=17.82g$

Molality = $\frac{3.6\times 10^{-4}\times 1000}{17.82g}=0.020$

Thus approximate molality of $CO_2$ in this solution is 0.020 m

5 0

4 years ago

Ammonia (NH3) is one of the most common chemicals produced in the united states. it is used to make fertilizer and other product

Greeley [361]

Answer:

a) N2 is the limiting reactant

b) 1215.9 grams NH3

c) 2283.6 grams H2

Explanation:

Step 1: Data given

Mass of N2 = 1000 grams

Molar mass N2 = 28 g/mol

Mass of H2 = 2500 grams

Molar mass H2 = 2.02 g/mol

Step 2: The balanced equation

N2(g) +3H2(g) → 2NH3(g)

Step 3: Calculate moles N2

Moles N2 = mass N2 / molar mass N2

Moles N2 = 1000 grams / 28.0 g/mol

Moles N2 = 35.7 moles

Step 4: Calculate moles H2

Moles H2 = 2500 grams / 2.02 g/mol

Moles H2 = 1237.6 moles

Step 5: Calculate limiting reactant

For 1 mol N2 we need 3 moles H2 to produce 2 moles NH3

N2 is the limiting reactant. There will be consumed 35.7 moles.

H2 is in excess. There will react 3*35.7 = 107.1 moles

There will remain 1237.6 - 107.1= 1130.5 moles H2

This is 1130.5 * 2.2 = 2283.6 grams H2

Step 6: Calculate moles NH3

For 1 mol N2 we need 3 moles H2 to produce 2 moles NH3

For 35.7 moles N2 we'll have 2*35.7 = 71.4 moles NH3

Step 7: Calculate mass NH3

Mass NH3 = moles NH3 * molar mass NH3

Mass NH3 = 71.4 moles * 17.03 g/mol

Mass NH3 = 1215.9 grams NH3

7 0

3 years ago

CAN SOMEONE HELP ME WITH THIS

cupoosta [38]

Answer: it is one parent

and a

Explanation:

5 0

3 years ago