Answer:
27.64 liters
Explanation:
From the balanced equation, 2 moles of K2Cr2O7 requires 3 moles of CH3OH.
Mole of CH3OH = 1.9/32.04 = 0.0593 mole
Mole of K2Cr2O7 that will require 0.0593 mole of CH3OH:
2 x 0.0593/3 = 0.0395 mole
mole = molarity x volume
Volume of K2Cr2O7 needed = 0.0395/0.00143
= 27.64 Liter
<em>Hence, 27.64 liters of 0.00143 M K2Cr2O7 will be required to titrate 1.90 g of CH3OH dissolved in 50.0 mL of solution</em>
(57.0 g B2O3 / (69.6202 g B2O3/mol) x (4mol BCI3 / 2 mol B2O3) = 1.64 mol BC13
(44.7 g C12) / (70.9064 g C12/mol) x (4mol BCI3 / 6mol C12) = 0.42027 mol BC13
(68.8 g C) / (12.01078 G C/mol) x (4mol BCI3 / 3 mol C) = 7.63 mol BCI3
C12 is the limiting reactant.
(0.42027 mol BCI3) X (117 . 170 g BCI3/mol) = 49.2 g BCI3 in theory.
Alkali metals (metals ) group 1 - properties are ● they are good conductors of heat
● luster (shiny)
● malleable (can be broken down into thin sheets)
● ductile
●lose electrons to form (+) ions
Answer: D. Low temperatures are best to maximize the solubility
Explanation:
Answer:
A patient cholesterol level and blood measures 149 mg/dL. What is the patients cholesterol level in grams per liter?
Explanation:
A patient cholesterol level and blood measures 149 mg/dL. What is the patients cholesterol level in grams per liter?
