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3 years ago

I will give out brainliest tell me the reason 2

Mathematics

2 answers:

lubasha [3.4K]3 years ago

7 0

late answer, for the people who came across it looking for the answer. its d! <3

Rashid [163]3 years ago

5 0

Answer:

D bc you keep going up by 60m/1hr

Step-by-step explanation:

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Please help, I'm very lost with this question

DIA [1.3K]

Firstly, let's solve for the third interior angle of the triangle. Interior angles of all triangles add to equal 180 degrees; to find the third interior angle, set the sum of the two known angle measures and the third angle measure, x, equal to 180 and solve.

180 = 75 + 50 + x
180 = 125 + x
55 = x

Now that we know all interior angle measures, we can begin to name the sides from shortest to longest.

The shortest side will always be opposite the smallest interior angle - in this case, angle H. This rule applies to both the other sides and angles; the longest side is opposite the largest interior angle, which in this case is angle G. (This means the second-largest angle is opposite the second-longest side - the sole remaining angle.)

The order of sides from shortest to longest: side IG, side GH, side HI.

Answer:
B

8 0

4 years ago

Please help!!! Refer to the spinner. Find P (even or not shaded). A. 2/3 B. 1/2

scZoUnD [109]

It’s bbbbbbbbbbbbbbbbbbbb

5 0

3 years ago

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Hellooo how are you guys doing today

OLEGan [10]

Answer:

I'm good yet tired lol how are you!

3 0

3 years ago

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Write the equation -4x^2+9y^2+32x+36y-64=0 in standard form. Please show me each step of the process!

IgorC [24]

Hey there, hope I can help!

$-4x^2+9y^2+32x+36y-64=0$

$\mathrm{Add\:}64\mathrm{\:to\:both\:sides} \ \textgreater \ 9y^2+32x+36y-4x^2=64$

$\mathrm{Factor\:out\:coefficient\:of\:square\:terms} \ \textgreater \ -4\left(x^2-8x\right)+9\left(y^2+4y\right)=64$

$\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}4$
$-\left(x^2-8x\right)+\frac{9}{4}\left(y^2+4y\right)=16$

$\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}9$
$-\frac{1}{9}\left(x^2-8x\right)+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}$

$\mathrm{Convert}\:x\:\mathrm{to\:square\:form}$
$-\frac{1}{9}\left(x^2-8x+16\right)+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)$

$\mathrm{Convert\:to\:square\:form}$
$-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)$

$\mathrm{Convert}\:y\:\mathrm{to\:square\:form}$
$-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y^2+4y+4\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right)$

$\mathrm{Convert\:to\:square\:form}$
$-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y+2\right)^2=\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right)$

$\mathrm{Refine\:}\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right) \ \textgreater \ -\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y+2\right)^2=1$

$Refine\;once\;more\;-\frac{\left(x-4\right)^2}{9}+\frac{\left(y+2\right)^2}{4}=1$

For me I used
$\frac{\left(y-k\right)^2}{a^2}-\frac{\left(x-h\right)^2}{b^2}= 1$
$As\;\mathrm{it\;\:is\:the\:standard\:equation\:for\:an\:up-down\:facing\:hyperbola}$

I know yours is an equation which is why I did not go any further because this is the standard form you are looking for. I would rewrite mine to get my hyperbola standard form. However the one I have provided is the form you need where mine would be.
$\frac{\left(y-\left(-2\right)\right)^2}{2^2}-\frac{\left(x-4\right)^2}{3^2}=1$

Hope this helps!

4 0

4 years ago

Mr queen has 256 crowns. He plans to sell them for 2 dollars each. How many does each crown cost in total ?

Alex_Xolod [135]

Answer:

$512

Step-by-step explanation:

If each crown is 2 dollars, then 256 x 2 would be the answer. The answer would be 512.

7 0

3 years ago

Read 2 more answers