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sukhopar [10]
2 years ago
12

CAN SOMEONE PLEASE HELP ME! TODAY IS MY LAST DAY!! WILL MARK BRAINLIEST

Mathematics
1 answer:
finlep [7]2 years ago
7 0

The given triangle is a right-angled triangle. This means that special trig identities can be applies

<u>These identities are as follows:</u>

sin (theta) = opposite / hypotenuse

cos (theta) = adjacent / hypotenuse

tan (theta) = opposite / adjacent

<u>Now, for the unknown theta in the triangle:</u>

The opposite side is 16 and the hypotenuse is 20

This means that we will use the <u>sin</u> not the cos as Bob did

<u>The solution will be as follows:</u>

sin (theta) = opposite / hypotenuse

sin (theta) = 16 / 20

theta = sin^-1(16/20)

theta = 53.13°

Hope this helps :)

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See explanation and hopefully it answers your question.

Basically because the expression has a hole at x=3.

Step-by-step explanation:

Let h(x)=( x^2-k ) / ( hx-15 )

This function, h, has a hole in the curve at hx-15=0 if it also makes the numerator 0 for the same x value.

Solving for x in that equation:

Adding 15 on both sides:

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Dividing both sides by h:

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For it be a hole, you also must have the numerator is zero at x=15/h.

x^2-k=0 at x=15/h gives:

(15/h)^2-k=0

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Or

Lim x->15/h ( x^2-(225/h^2) ) / ( hx-15 ) you couldn't use direct substitution because of the hole at x=15/h.

We were ask to evaluate

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Comparing the two limits h=5 and k=225/h^2=225/25=9.

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