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sukhopar [10]
3 years ago
12

CAN SOMEONE PLEASE HELP ME! TODAY IS MY LAST DAY!! WILL MARK BRAINLIEST

Mathematics
1 answer:
finlep [7]3 years ago
7 0

The given triangle is a right-angled triangle. This means that special trig identities can be applies

<u>These identities are as follows:</u>

sin (theta) = opposite / hypotenuse

cos (theta) = adjacent / hypotenuse

tan (theta) = opposite / adjacent

<u>Now, for the unknown theta in the triangle:</u>

The opposite side is 16 and the hypotenuse is 20

This means that we will use the <u>sin</u> not the cos as Bob did

<u>The solution will be as follows:</u>

sin (theta) = opposite / hypotenuse

sin (theta) = 16 / 20

theta = sin^-1(16/20)

theta = 53.13°

Hope this helps :)

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