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3 years ago

CAN SOMEONE PLEASE HELP ME! TODAY IS MY LAST DAY!! WILL MARK BRAINLIEST

Mathematics

1 answer:

finlep [7]3 years ago

7 0

The given triangle is a right-angled triangle. This means that special trig identities can be applies

These identities are as follows:

sin (theta) = opposite / hypotenuse

cos (theta) = adjacent / hypotenuse

tan (theta) = opposite / adjacent

Now, for the unknown theta in the triangle:

The opposite side is 16 and the hypotenuse is 20

This means that we will use the sin not the cos as Bob did

The solution will be as follows:

sin (theta) = opposite / hypotenuse

sin (theta) = 16 / 20

theta = sin^-1(16/20)

theta = 53.13°

Hope this helps :)

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Note: you did not provide the answer options, so I am, in general, solving this query to solve your concept, which anyways would clear your concept.

Answer:

Please check the explanation.

Step-by-step explanation:

Given the inequality

$3x-4y>5$

All we need is to find any random value of 'x' and then solve the inequality.

For example, putting x=3

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$\mathrm{Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)}$

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$y$

So, at x = 3, the calculation shows that the value of y must be less

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Let us take the random y value that is less than 1.

As y=0.9 < 1

so putting y=0.9 in the inequality

$3\left(3\right)-4\left(0.9\right)$

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$=5.4$

As 5.4 > 5

Means at x=3, and y=0.9, the inequality is satisfied.

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3 years ago

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Answer:

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$\left[\begin{array}{cccc}0&1&1&1\\0&0&1&1\\0&0&0&1\\0&0&0&0\end{array}\right]$

for b

b) {(1, 1), (1, 4), (2, 2), (3, 3), (4, 1)}

$\left[\begin{array}{cccc}1&0&0&1\\0&1&0&0\\0&0&1&0\\1&0&0&0\end{array}\right]$

for c) {(1, 2), (1, 3), (1, 4), (2, 1), (2, 3), (2, 4), (3, 1), (3, 2), (3, 4), (4, 1), (4, 2), (4, 3)}

$\left[\begin{array}{cccc}0&1&1&1\\1&0&1&1\\1&1&0&1\\1&1&1&0\end{array}\right]$

for d d) {(2, 4), (3, 1), (3, 2), (3, 4)}

$\left[\begin{array}{cccc}0&0&0&0\\0&0&0&1\\1&1&0&1\\0&0&0&0\end{array}\right]$

Step-by-step explanation:

in matrix, arrays are placed in rows , which represents the horizontal sides from left to right, while arrays in the column are placed vertically from top to bottom. Here, we placed the arrays in a 4x4 matrix

for a a) {(1, 2), (1, 3), (1, 4), (2, 3), (2, 4), (3, 4)}

$\left[\begin{array}{cccc}0&1&1&1\\0&0&1&1\\0&0&0&1\\0&0&0&0\end{array}\right]$

for b

b) {(1, 1), (1, 4), (2, 2), (3, 3), (4, 1)}

$\left[\begin{array}{cccc}1&0&0&1\\0&1&0&0\\0&0&1&0\\1&0&0&0\end{array}\right]$

for c) {(1, 2), (1, 3), (1, 4), (2, 1), (2, 3), (2, 4), (3, 1), (3, 2), (3, 4), (4, 1), (4, 2), (4, 3)}

$\left[\begin{array}{cccc}0&1&1&1\\1&0&1&1\\1&1&0&1\\1&1&1&0\end{array}\right]$

for d d) {(2, 4), (3, 1), (3, 2), (3, 4)}

$\left[\begin{array}{cccc}0&0&0&0\\0&0&0&1\\1&1&0&1\\0&0&0&0\end{array}\right]$

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Step-by-step explanation:

Apply the point-slope formula here: y - k = m(x - h) becomes

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3 years ago