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Oksana_A [137]
3 years ago
10

The first successful perpetual motion machine was invented in 1859. True OR False

Chemistry
1 answer:
STALIN [3.7K]3 years ago
4 0

Answer:

false

Explanation:

made in 12th centry

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The difference between fission and fusion is that....
aliina [53]
Fusion and fission are both nuclear reactions that produce energy, but fusion is two nucleus joining (think about fuse or fusing), while fission is a nucleus splitting (think about fissure)

so the correct answer is <span>C. Fission is the splitting of a nucleus</span>
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A constant volume of oxygen is heated from 100°C to 155°C. The
dybincka [34]

Answer:

= 3.56 atm

Explanation:

Using Boyle's law which states that the volume of a given mass of gas is inversely proportional to the pressure and Charles law states the volume of a given mass of gas is directly proportional to the temperature.

P1/T1 = P2/T2

P1 = 3.1 atm, T1 = 100'C = 100+273 = 373K

T2 = 155'C = 155 + 273 = 428K

3.1/ 373 = P2 / 428

Cross multiply

373 × P2 = 3.1 × 428

373×P2 = 1326.8

Divide both sides by 373

P2 = 1326.8 ÷ 373

P2 = 3.56 atm

I hope this was helpful, please mark as brainliest

3 0
3 years ago
What happens to the temperature when carbon dioxide is added to the atmosphere
nordsb [41]

The temperature increases due to CO2. Hence global warming is caused by CO2.

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3 years ago
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In what way is DNA a code
Alex777 [14]

Answer:

Basically it is instructions of how some protein, organ, or pretty much any living organism is to be made. Similar to how different lines of code correspond to how to the software looks or behaves as, DNA acts as codes to make different organs, living beings, cells, pretty much all the living things.

Explanation:

7 0
3 years ago
Calculate the total energy, in kilojoules, that is needed to turn a 46 g block
gogolik [260]

<u>Answer:</u> The amount of heat absorbed is 141.004 kJ.

<u>Explanation:</u>

In order to calculate the amount of heat released while converting given amount of steam (gaseous state) to ice (solid state), few processes are involved:

(1): H_2O (s) (-25^oC, 248K) \rightleftharpoons H_2O(s) (0^oC,273K)

(2): H_2O (s) (0^oC, 273K) \rightleftharpoons H_2O(l) (0^oC,273K)  

(3): H_2O (l) (0^oC, 273K) \rightleftharpoons H_2O(l) (100^oC,373K)

(4): H_2O (l) (100^oC, 373K) \rightleftharpoons H_2O(g) (100^oC,373K)

Calculating the heat absorbed for the process having the same temperature:

q=m\times \Delta H_{(f , v)}       ......(i)

where,

q is the amount of heat absorbed, m is the mass of sample and \Delta H_{(f , v)} is the enthalpy of fusion or vaporization

Calculating the heat released for the process having different temperature:

q=m\times C_{s,l}\times (T_2-T_1)      ......(ii)

where,

C_{s,l} = specific heat of solid or liquid

T_2\text{ and }T_1 are final and initial temperatures respectively

  • <u>For process 1:</u>

We are given:

m=46g\\C=2.108J/g^oC\\T_2=0^oC\\T_1=-25^oC

Putting values in equation (i), we get:

q_1=46g\times 2.108J/g^oC\times (0-(-25))\\\\q_1=2424.2J

  • <u>For process 2:</u>

We are given:

m=46g\\\Delta H_{fusion}=334J/g

Putting values in equation (i), we get:

q_2=46g\times 334J/g\\\\q_2=15364J

  • <u>For process 3:</u>

We are given:

m=46g\\C=4.186J/g^oC\\T_2=100^oC\\T_1=0^oC

Putting values in equation (i), we get:

q_3=46g\times 4.186J/g^oC\times (100-0)\\\\q_3=19255.6J

  • <u>For process 4:</u>

We are given:

m=46g\\\Delta H_{vap}=2260J/g

Putting values in equation (i), we get:

q_4=46g\times 2260J/g\\\\q_4=103960J

Calculating the total amount of heat released:

Q=q_1+q_2+q_3+q_4

Q=[(2424.2)+(15364)+(19255.6)+(103960)]

Q=141003.8J=141.004kJ                  (Conversion factor: 1 kJ = 1000J)

Hence, the amount of heat absorbed is 141.004 kJ.

7 0
3 years ago
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