At 330 K the vapor pressure of pure n-pentane is 1.92 atm and the vapor pressure of pure n-octane is 0.07 atm. If 330K is the no
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When an electron occupies an orbital of an atom singly, rather than an electron pair such electron is said to be an unpaired electron. Each atomic orbital of an atom specified by quantum numbers can contain a maximum of two electrons having opposite spins, electron pair.
The numbers of unpaired electrons are determined by the electronic configuration of an atom. The electronic configuration of calcium, is:
or
Since, from the electronic configuration it is clear that the number of electrons in valence orbital that is is 2 that means the electrons are paired up in the valence orbital so, there are no unpaired electrons present in
.
Hence, the number of unpaired electrons in is 0.
<h3>Answer:</h3>
1.5 × 10²³ atoms Mn
<h3>General Formulas and Concepts:</h3><u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
- Left to Right
<u>Chemistry</u>
<u>Atomic Structure</u>
- Using Dimensional Analysis
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<u>Step 1: Define</u>
0.25 mol Mn
<u>Step 2: Identify Conversions</u>
Avogadro's Number
<u>Step 3: Convert</u>
- Set up:
- Multiply:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 2 sig figs.</em>
1.5055 × 10²³ atoms Mn ≈ 1.5 × 10²³ atoms Mn