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maksim [4K]
3 years ago
5

A mixture of 0.220 moles CO, 0.350 moles H2 and 0.640 moles He has a total

Chemistry
1 answer:
emmasim [6.3K]3 years ago
6 0

Answer:

P(H₂) = 0.8533 atm

Explanation:

n(CO) = 0.220 mole

n(H₂)  = 0.350 mole

n(He) = 0.640 mole

_______________

∑ n  =  1.210 moles

mole fraction => X(H₂) = 0.350/1.210 = 0.2892

Dalton's Law of Partial Pressures => P(H₂) = X(H₂)·P(ttl) = 0.2892(2.95 atm) = 0.8533 atm

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Answer:

21.6 g

Explanation:

The reaction that takes place is:

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First we<u> convert the given masses of both reactants into moles</u>, using their <em>respective molar masses</em>:

  • 9.6 g CH₄ ÷ 16 g/mol = 0.6 mol CH₄
  • 64.9 g O₂ ÷ 32 g/mol = 2.03 mol O₂

0.6 moles of CH₄ would react completely with (2 * 0.6) 1.2 moles of O₂. As there are more O₂ moles than required, O₂ is the reactant in excess and CH₄ is the limiting reactant.

Now we <u>calculate how many moles of water are produced</u>, using the <em>number of moles of the limiting reactant</em>:

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4 0
2 years ago
Suppose you find a rock that contains some potassium-40 (half-life of 1.3 billion years). you measure the amount and determine t
Alborosie
Equation for Half life :
A = a(0.5)^(t/h)
A is current amount, "a" is initial amount, h is halflife, t is time

5 = 40(0.5)^(t/1.3x10^9)
5/40 = (0.5)^(t/1.3x10^9)
take the log of both sides , power rule
Log(5/40) = (t/1.3x10^9) * Log(0.5)
(1.3x10^9) * Log(5/40) / Log(0.5) = t
3.9x10^9 years = t

And if you think about what a half life is, the time it take for the amount to reduce to half.
40/2 = 20
20/2 = 10
10/2 = 5
It went through 3 half-lifes
3 * 1.3x10^9 = 3.9x10^9 years

7 0
3 years ago
1. 750 x 10^3 ng to g​
Temka [501]

Answer:

1.750×10^-6 g

Explanation:

we know n is 10^-9. all you have to do is to replace n with 10^-9.

so the answer is

1.750×10^3×10^-9 g

which is equal to 1.750×10^-6 g

if anything is unclear, ask freely.

4 0
3 years ago
There are two open cans of soda on the table one can was just take it on the refrigerator and the other was taken from the cup b
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8 0
3 years ago
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2) repulsion in 3p shell in sulfur between 2 paired electrons is higher, so it is easier to remove that electron.

5 0
3 years ago
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