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2 years ago

A mixture of 0.220 moles CO, 0.350 moles H2 and 0.640 moles He has a total

Chemistry

1 answer:

emmasim [6.3K]2 years ago

6 0

Answer:

P(H₂) = 0.8533 atm

Explanation:

n(CO) = 0.220 mole

n(H₂) = 0.350 mole

n(He) = 0.640 mole

_______________

∑ n = 1.210 moles

mole fraction => X(H₂) = 0.350/1.210 = 0.2892

Dalton's Law of Partial Pressures => P(H₂) = X(H₂)·P(ttl) = 0.2892(2.95 atm) = 0.8533 atm

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Distillation is a process of vaporization a substance and chilling the vapor to collect it back the liquid form. How much heat i

stich3 [128]

Answer:

72 kJ of heat is removed.

Explanation:

First, the ethanol vapor will reduce its temperature until the temperature of the boiling point, then it will occur a phase change from vapor to liquid, and then the temperature of the liquid will decrease. The total heat will be:

Q = Q1 + Q2 + Q3

Q1 = n*cv*ΔT1, Q2 = m*Hl, and Q3 = n*cl*ΔT2

Where n is the number of moles, cv is the specific heat of the vapor (65.44 J/K.mol, cl is the specific heat of the liquid (111.46 J/K.mol), Hl is the heat of liquefaction (-836.8 J/g), m is the mass, and ΔT is the temperature variation (final - initial).

Q = n*cv*ΔT1 + m*Hl + n*cl*ΔT2

The molar mass of ethanol is 46 g/mol, and the number of moles is the mass divided by the molar mass:

n = 74.2/46 = 1.613 moles

Q = 1.613*65.44*(78.37 - 83) + 74.2*(-836.8) + 1.613*111.46*(26 - 78.37)

Q = -72000 J

Q = -72 kJ (because it is negative, it is removed)

3 0

3 years ago

Write the equation for the dissociation of hcl when hcl is dissolved in water.

kotykmax [81]

Answer:

HCl -> H+ + Cl- (monoprotic acid)

3 0

2 years ago

Draw the organic product formed when ch3ch2c≡c−na+ reacts with (ch3)2chch2ch2cl. click the "draw structure" button to launch the

Viktor [21]

Explanation:

Given that sodium butylite is reacting with 1-chloro-3-methyl butane. In a reaction 6-methyl nona-3-yne and sodium chloride will be obtained as product.

The chemical reaction:

$CH_3-CH_2C\equiv C-Na^++(CH_3)_2CH-CH_2-CH_2-Cl\rightarrow CH_3-CH_2C\equiv C-CH_2-CH_2-(CH_3)_2+NaCl$

The reaction is also attached as image for reference.

6 0

3 years ago

If the pressure on the surface of water in the liquid stato

Novosadov [1.4K]

The water will boil at C) 80°C

<h3>Further explanation</h3>

Given

Vapour pressure of water = 47 kPa

Required

Boiling point of water

Solution

We can use the Clausius-Clapeyron equation :

$\tt ln(\dfrac{P_1}{P_2})=\dfrac{-\Delta H_{vap}}{R}(\dfrac{1}{T_1}-\dfrac{1}{T_2})$

Vapour pressure of water at boiling point 100°C=101.325 kPa

ΔH vap for water at 100°C=40657 J/mol

R = 8.314 J/mol K

T₁=boiling point of water at 101.325 kPa = 100+273=373 K

Input given values :

$\tt ln\dfrac{101.325}{47}=\dfrac{-40657}{8.314}(\dfrac{1}{373}-\dfrac{1}{T_2})\\\\0.7682=4890.1852(\dfrac{1}{373}-\dfrac{1}{T_2})\\\\0.0001571=(\dfrac{1}{373}-\dfrac{1}{T_2})\\\\\dfrac{1}{T_2}=0.00283\rightarrow T_2=353~K=80^oC$

6 0

3 years ago

How can the strength of an acid be determined using titration? (100 POINTS!)

Ad libitum [116K]

Answer:

Explanation:

We use the method of titration

A titration involves finding the unknown concentration of one solution by reacting it with a solution of known concentration. The solution of unknown concentration (the analyte) is usually placed in an Erlenmeyer flask, while the solution of known concentration (titrant) is placed in a burette. The titrant is added to the analyte until the endpoint is reached usually determined by a color change. Calculations are then performed to find the unknown concentration of the analyte. Titrations are typically performed on acid/base reactions but are not limited to them.

Macid x Vacid = Mbase x Vbase

Macid = Molarity of the acid

Vacid = Volume of the acid

Mbase = Molarity of the base

Vbase = Volume of the base

If the titrant and analyte have a 1:1 mole ratio, the equation above can be used to determine the unknown concentration, if the ratio is not 1:1 then a modified version should be used

I hope you find this helpful.

7 0

2 years ago

Read 2 more answers