E^2x=(42-12)/3, that is easy
Then, the magic!
Ln(e^2x)=Ln[(42-12)/3]
2x.Ln(e)=Ln[(42-12)/3]. "Ln(e)=1"
X={Ln[(42-12)/3]}/2
Good luck!
M.
<h3>
Answer: 4 minutes</h3>
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Explanation:
Let's say that this tub is 72 gallons. I picked this number since 12*6 = 72. You can pick any number you want, but I picked this number so we end up with whole number results as shown below.
Tap X can fill the 72 gallon tub in 12 minutes. Its rate is 72/12 = 6 gallons per minute. Tap Y has a rate of 12 gallons per minute because 72/6 = 12.
Add the two unit rates: 6+12 = 18
If the two taps are opened at the same time, then they will work at a rate of 18 gallons per minute.
Let x be the number of minutes. The expression 18x represents how much of the tub is full after x minutes. Set this equal to the 72 we started with earlier and solve for x.
18x = 72
x = 72/18
x = 4
It will take 4 minutes if both taps are running at the same time.
To find the total weight of error subtract the measured weight from the actual weight
3900kg (actual weight) - 3867kg (measured weight) = 33 kg erorr
Answer:
17 - i
Step-by-step explanation:
<u>Step 1: FOIL out</u>
(1 - 3i)(2 + 5i)
(2) + (1 * 5i) + (-3i * 2) + (-3i * 5i)
2 + 5i - 6i - 15i^2
2 - i + 15
<em>17 - i</em>
<em />
Answer: 17 - i
