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lyudmila [28]
3 years ago
8

A wave is traveling through a string and six waves pass a point in three seconds what is the frequency of the wave

Physics
1 answer:
Butoxors [25]3 years ago
8 0

Frequency of the wave is 2 per second

Explanation:

  • Frequency is the number of times waves pass at a particular point of time. Here, given time period = 3 s and number of waves that pass in 3 seconds = 6. Find the frequency of the wave per second.
  • Frequency is given by the formula

f = 1/T, where f is the frequency and T is the time period

  • For 3 seconds, frequency is 6

3 seconds ⇒ 6 waves

⇒ 1 second = 6/3 = 2 waves per second

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A rugby player runs with the ball directly toward his opponent's goal, along the positive direction of an x axis. He can legally
Over [174]

Answer:

minimum angle is 128.69°

Explanation:

given data

player velocity with respect ground v1 = 3.5 m/s

ball velocity with respect himself v2 = 5.6 m/s

to find out

smallest angle

solution

we know ball velocity with respect field will be

ball velocity = v1  +v2

ball velocity = 3.5 + 5.6 = 9.1m/s

we consider angle that player hit ball is θ

then by as per figure triangle

cosθ = \frac{v1}{v2}

cosθ = \frac{3.5}{5.6}

θ = 51.31

so minimum angle is 180 - 51.31 = 128.69°

6 0
3 years ago
I need help on this
ZanzabumX [31]
What is the question asking?
6 0
3 years ago
The weight of a person is 500N and his foot imprint area is 0.5m^2.Calculate the total pressure exerted by person when he stands
Ghella [55]

Answer:

Pressure on both feet will be 500N/m^2  

Explanation:

Weight of the person F = 500 N

Area of foot print A=0.5m^2

Area of both the foot A=2\times 0.5=1m^2

We have to find pressure on both the feet

Pressure is equal to ratio of force and area

So pressure P=\frac{F}{A}

P=\frac{500}{1}=500N/m^2

So the pressure on both feet will be 500N/m^2 when person stands on both feet.

7 0
3 years ago
Any body moving with simple harmonic motion is being acted on by a force that is:__________.
Stella [2.4K]

Answer:

B

Explanation:

Because this oscillations occur when the restoring force is directly proportional to displacement, given as

F=-kx

Where k= force constant

X= displacement

6 0
3 years ago
A boat is able to move through still water at 20 m/s. It makes a round trip to a town 3.0 km upstream. If the river flows at 5m/
Salsk061 [2.6K]

Answer:

Option e) 320 s

Explanation:

Here, distance = 3.0 km = 3000 m

The velocity of boat when it is going upstream;

Upstream velocity = velocity of boat in still water - velocity of river flow

So, Upstream velocity =20m/s-5m/s=15m/s

So,Time to go upstream

(t_{1}) =\frac{Distance}{Velocity}=\frac{3000m}{15m/s} =200 s

The velocity of boat when it is going downstream;

Downstream velocity = velocity of boat in still water + velocity of river flow

So, Downstream velocity =20m/s+5m/s=25m/s

So,Time to go downstream

(t_{2}) =\frac{Distance}{Velocity}=\frac{3000m}{25m/s} =120 s

So, total time (t) = t_{1}+t_{2}=200s+120 s=320s

Option E is the correct answer.

3 0
3 years ago
Read 2 more answers
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