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Mila [183]
3 years ago
9

The speed limit on Highway 85 is 65 mi/h. What is it in m/s?

Physics
2 answers:
Paladinen [302]3 years ago
4 0

Answer:

It is 65 miles per hour, that's to say if you are going to drive for an hour you will travel 65 miles. or if you travel 65 miles you have been driving for an hour.

Gelneren [198K]3 years ago
3 0

Answer:

29 m/s

Explanation:

65 mi/hr (1 hr/3600s)(5280 ft/mi)(12 in/ft)(2.54 cm/in)(1 m/100cm) = 29.0576

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The air pressure inside a car tire is
Valentin [98]

Answer:

0.137m²

Explanation:

Pressure = Force/Area

Given

Force = 41,500N

Pressure = 3.00atm

since 1atm = 101325.00 N/m²

3atm = 3(101325.00)

3atm = 303,975N/m²

Pressure = 303,975N/m²

Get the area

Area = Force/Pressure

Area = 41500/303,975

Area = 0.137m²'

Hence the surface area of the  inside of the tire is 0.137m²

7 0
3 years ago
When an object moved in a circle ___ acts to accelerate the object toward the center of that cirlce
Irina18 [472]
Centripital acceleration. When an object moves in a circle, centripital acceleration acts to accelerate the object towards the center of that circle
7 0
3 years ago
Read 2 more answers
a car headed north at 15 m/s accelerates for 4.25 s to reach a velocity of 28.3 m/s. What is the acceleration of the car?
Liono4ka [1.6K]

<u>Answer:</u>

The acceleration of the car is 3.13 m/s^2

<u>Explanation:</u>

In the question it is given that car initially heads north with a velocity 15 m/s. It then accelerates for 4.25 s and in the end its velocity is 28.3 m/s.

initial velocity u = 15 m/s

time t=4.25 s

final velocity v=28.3 m/s

The equation of acceleration is

a= \frac{(v-u)}{t}

= \frac{(28.3-15)}{4.25} =  \frac {13.3}{4.25} =3.13m/s^2

The value of acceleration is positive, here since the car is speeding up. If it was slowing down the value of acceleration would be negative.

7 0
3 years ago
How does the intensity of a sound wave change if the distance from the
Alex17521 [72]

Answer:

The new intensity decreases by a factor of 16.

Explanation:

The intensity of sound wave is given by :

I=\dfrac{P}{A}

P is power

A is area

I=\dfrac{P}{4\pi r^2}

or

I\propto \dfrac{1}{r^2}, r is distance from the source

If the distance from the  source is increased by a factor of 4, r' = 4r

So,

I'=\dfrac{1}{r'^2}\\\\I'=\dfrac{1}{(4r)^2}\\\\I'=\dfrac{1}{16}\times \dfrac{1}{r^2}\\\\I'=\dfrac{I}{16}

So, the new intensity decreases by a factor of 16.

8 0
3 years ago
Which of the following is defined as an area of the body surface that is innervated by a single spinal​ nerve?
romanna [79]

Answer:

Dermatome. (Ans. C).

Explanation:

Dermatome is defined as the area of the human anatomy skin which is supplied by single spinal sensory nerve root. At the spinal cord these spinal sensory nerve enter the nerve root, and the branches of spinal sensory reach to the periphery of the body.

The sensory nerve which is present in the periphery of the body are the type of nerve which helps to transmit signals from sensation such as pain, temperature, etc. to the spinal cord from some specific area of the anatomy.

3 0
3 years ago
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