The given equation is: 
To find the line perpendicular to it, we interchange coefficients and switch the signs of one coefficient.
The equation to a line perpendicular to it is:
$ 2y-x=c$
where, $c$ is some constant we have determine using the condition given.
It passes through $(2,-1)$
Put the point in our equation:
$2(-1)-(2)=c$
$c=-2-2$
$c=-4$
The final equation is:
$\boxed{ 2y-x=-4}$
Answer:
It is not
Step-by-step explanation:
It is not because this is an exponential function
y=x^2
1^2=1
2^2=4
3^2=9
4^2=16
Answer:
Step-by-step explanation:
The difference of the rational and and irrational number is always an irrational number.
Correct choice is B
Step-by-step explanation:
2x^2+6x=36
x^2+3x=12
x^2+3x-12=0
x=(-3+(57)^0.5)/2 or x=(-3-(57)^0.5)/2