Answer:
Step-by-step explanation:
check attachment
f(x,y)=xy Δf(2,5)
fx=y = 5
fy=x = 2
Gradient Vector:
<5,2>
Tangent Vector:
0=fx(x-2) + fy(y-5)
0=5(x-3) + 2(y-2)
11=5x+2y
What is the equation in slope-intercept form of the line that passes through points (-4,2) and (12,6)
1 answer:
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