Answer:
True
Explanation:
Lose of water content in our body through sweating and lose of essential salts such as potassium and sodium causes heat cramps...
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Explanation:
Given parameters:
Distance hopped = 84m
Displacement = 84m due east
Time = 7s
Unknown:
Speed of kangaroo = ?
Velocity of kangaroo = ?
Solution:
To solve this problem,
Speed = = = 12m/s
Velocity = = = 12m/s due east
Answer:
Explanation:
The relation between the de Broglie wavelength and the momentum of the particle is given by
where, m is the mas of the particle and v be the velocity of the particle and h be the Plank's constant.
So, the de broglie wavelength of proton is given by
.... (1)
The de broglie wavelength of electron is given by
.... (2)
Divide equation (2) by equation (1), we get
As the mass of proton is much more than the mass of electron, so the de broglie wavelength of electron is more than the de Broglie wavelength of proton.
Answer:
Explanation:
It is given that,
Speed of one quoll around a curve, v = 3.2 m/s (maximum speed)
Radius of the curve, r = 1.4 m
On the curve, the centripetal force is balanced by the frictional force such that the coefficient of frictional is given by :
So, the coefficient of static friction between the quoll's feet and the ground in this trial is 0.74. Hence, this is the required solution.
Answer:
(a) 2.624
(b) 1.334
Explanation:
The given data in the question is:
Mass = 2.95 kg
Spring constant "k" = 820 N/m
Compression of Spring "x" = 0.0800m
Using this data and the equation to find the answer for spring potential energy:
spring potential energy = 1/2 kx²
= 1/2 (820 N/m)(0.0800m)²
= 2.624 Joules
(b) - It is given that the surface is friction-less which means no loss of energy during the motion of spring. This means that all the potential energy possessed by the spring converts to Kinetic Energy of the block. We can equate spring potential energy with Kinetic energy to find the block's speed as below:
Kinetic Energy = 1/2mv² where "m" is mass and "v" is velocity of the object
1/2mv² = spring potential energy (found in part "a" above)
1/2(2.95 kg)v² = 2.624 Joules
v² = (2.624 x 2) / 2.95
v² = 1.779
v = √1.779
v = 1.334 m/s