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STatiana [176]
2 years ago
7

If you wanted to

Physics
1 answer:
VLD [36.1K]2 years ago
5 0

Answer:

Option C

Explanation:

According to the formula

  • \\ \boxed{\sf R=\rho\dfrac{\ell}{A}}

So

If we use wide wire we increase the area of cross section so resistance decreases

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What is the relationship between dipole moment and boiling point?
Lelu [443]
The dipole moment of a molecule and its boiling point are directly varied. If the dipole moment is large, the attraction between the positive and negative charges of a molecule is strong thus, requiring stronger forces to break them. Hence, they will have higher boiling points. 
3 0
3 years ago
A 3.4kg aluminium ball has an apparent mass of 2.10kg when submerged in a particular liquid. Calculate the density of the liquid
Shalnov [3]

Answer:

1083.3kg/m ³

Explanation:

Given parameters:

Mass of aluminium ball = 3.4kg

Apparent mass of ball = 2.1kg

Unknown:

Density of the liquid = ?

Solution:

Density is is the mass per unit volume of any give substance;

         Density = \frac{mass}{volume}

     Now, we must understand that the apparent weight of the aluminium is the part of its weight supported by the fluid;

     

   Pl = \frac{Ml}{Vl}

   Pl = density of liquid

   Ml = mass of liquid

   Vl = volume of liquid

 Mass of liquid = Mal - Mapparent

       Mal = mass of aluminium

The volume of liquid displaced is the same as the volume of the aluminium according to Archimedes's principle;

              Ml = Pl x Vl

      Val = Vl

      Val volume of aluminium

      Vl = volume of liquid

            ****

        Pal = \frac{Mal}{Val}

       Val = \frac{Mal}{Pal}

       Val = volume of aluminium

       Mal = mass of aluminium

       Pal = density of aluminium

   *****

      Since the Val = Vl

          Ml = Pl x \frac{Mal}{Pal}

    Since

          Ml = Mal - Mapparent

                Mal - Mapparent  = Pl  x \frac{Mal}{Pal}

Pal = density of aluminium = 2712 kg/m ³

             3.4 - 2.1 = Pl x \frac{3.4}{2712}

                 1.3 = Pl x 0.00123

                    Pl = 1083.3kg/m ³

       

5 0
3 years ago
The area around a charged object that can exert a force on other charged objects is an electric ___
Ymorist [56]
Answer is:

Electric field.
8 0
4 years ago
When is friction bad
siniylev [52]

According to my research, Friction is bad when you get blisters that's when it can be harmful.

4 0
4 years ago
Read 2 more answers
Fermi energy of conduction electrons in silver is 0.548 J. Calculate the number of such electrons in unit cm3
ICE Princess25 [194]

Answer:

n=1.86*10^{-30}m^3

Explanation:

From the question we are told that:

Fermi energy of conduction electrons E_f=0.548J

Generally the equation for Fermi energy is mathematically given by

 E_f=\frac{3}{\pi}^2/3*\frac{h^2}{8m}*{n^{2/3}}

 E_f=\frac{3}{\pi}^2/3*\frac{h^2}{8m}*{n^{2/3}}

 {n^{2/3}}=\frac{E_f}{\frac{3}{\pi}^2/3*\frac{h^2}{8m}}

Where

h= Planck's constant

 {n^{2/3}}=\frac{E_f}{\frac{3}{\pi}^2/3*\frac{h^2}{8m}}

 {n^{2/3}}=\frac{0.548J}{3.62*10^{-19}}

 n=(1.51*10^{-20})^{3/2}

 n=1.86*10^{-30}m^3

3 0
3 years ago
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