1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
jeyben [28]
3 years ago
15

Anybody got any answers???

Physics
2 answers:
dexar [7]3 years ago
6 0

Answer:

b? to a?

Explanation:

belka [17]3 years ago
3 0

It converts mechanical energy to electrical.

Therefore, Option A is the correct answer

You might be interested in
You are driving down the highway late one night at 20 m/s when a deer steps onto the road 35m in front of you. Your reaction tim
8090 [49]

Answer:

- Distance between car and the deer when the car stopped = 20 m

- The time required for you to stop once you press the brakes = less than 5 s in order not to hit the deer.

Explanation:

Using the equations of motion,

In the 0.5 s reaction time, we need to first calculate how far he has travelled in that time.

a = 0 m/s² (Since the car is travelling at constant velocity)

x = ?

Initial velocity = u = 20 m/s

x = ut + at²/2

x = 20×0.5 + 0 = 10 m

From that moment,

a = - 10 m/s²

u = initial velocity at the start of the deceleration = 10 m/s

v = final velocity = 0 m/s

x = ?

v² = u² + 2ax

0² = 10² + 2(-10)(x)

20x = 100

x = 5 m

Total distance travelled from when the deer stepped onto the road = 10 + 5 = 15 m

Distance between car and the deer when the car stopped = 35 - 15 = 20 m

b) To determine the time required to stop once you step on the brakes

u = 10 m/s

t = ?

v = 0 m/s²

x = distance from when the brake was stepped on to the deer = 35 - 10 = 25 m

x = (u + v)t/2

25 = (10 + 0)t/2

10t = 50

t = 5 s

Meaning the time required to stop once you step on the brakes is less than 5s.

6 0
3 years ago
A satellite circles the Earth in an orbit whose radius is twice the Earth’s radius. The Earth’s mass is 5.98 x 1024 kg, and its
gavmur [86]

Hello!

Recall the period of an orbit is how long it takes the satellite to make a complete orbit around the earth. Essentially, this is the same as 'time' in the distance = speed * time equation. For an orbit, we can define these quantities:

d = 2\pi r ← The circumference of the orbit

speed = orbital speed, we will solve for this later

time = period

Therefore:

T = \frac{2\pi r}{v}

Where 'r' is the orbital radius of the satellite.

First, let's solve for 'v' assuming a uniform orbit using the equation:
v = \sqrt{\frac{Gm}{r}}

G = Gravitational Constant (6.67 × 10⁻¹¹ Nm²/kg²)

m = mass of the earth (5.98 × 10²⁴ kg)

r = radius of orbit (1.276 × 10⁷ m)

Plug in the givens:
v = \sqrt{\frac{(6.67*10^{-11})(5.98*10^{24})}{(1.276*10^7)}} = 5590.983 m/s

Now, we can solve for the period:

T = \frac{2\pi (1.276*10^7)}{5590.983} =\boxed{ 14339.776 s}

7 0
2 years ago
When changing a tire sized 195/75 R15 to a 5 percent lower profile, the correct tire size would be _____
valentinak56 [21]

Answer and explanation:

When you are changing a car tire, the most important thing is to keep the total diameter as equal as possible.

The total car tire diameter can be calculated as:

D_{tot orig}=\frac{195 \cdot 75}{2540 \cdot 2}+15''=26.5''

The profile of this tire is 75 (the higher/taller relation), therefore a 5 percent lower profile would be:

pr=0.95·75=71.25

The problem is that the profiles are normalized and the nearest profile available is 70.

If we take a theorical tire with a profile of 71.25:

D_{tot orig}=D_{new}\\\frac{195 \cdot 75}{2540 \cdot 2}+15''=\frac{X \cdot 71.25}{2540 \cdot 2}+15''\\X=205.26

The theorical tire size should be 205/71 R15.

If we look for a real tire size, we should look for a tire with a diameter nearest to 26.5'' and a profile of 70.

The best option for real tire size is: Tire 225/70 R14 (wheel diameter of 26.4'') or 205/70 R15 (wheel diameter of 26.3'').

3 0
3 years ago
Electric charges can only be transferred through a process called conduction.true or false
umka21 [38]

I'm going to say false hope that helped

5 0
3 years ago
Read 2 more answers
an object weighs 98 n on earth. How much does it weigh on planet x where the acceleration due to gravity in 6 m/s^2
Degger [83]
60 N because 98N=mg (here g= 9.8 on earth) thus mass can be calculated which is 98/9.8 = 10kg Now,new weight with g = 6m/s^2 =m×g' (here g' is new acceleration of the new planet) = 10×6=60N
7 0
3 years ago
Read 2 more answers
Other questions:
  • Which statement correctly describes the differences between positive and negative acceleration? Positive acceleration describes
    13·2 answers
  • Which is NOT a property of gold? Select one: a. rare b. malleable c. tarnishes d. corrosion resistant
    12·2 answers
  • Light incident on a glass sheet is partly reflected and partly refracted. How is the reflected ray different from the refracted
    13·1 answer
  • Assuming that Bernoulli's equation applies, compute the volume of water ΔV that flows across the exit of the pipe in 1.00 s . In
    11·1 answer
  • Pls help guys this is my 7th time posting XD​
    7·2 answers
  • Will give brainliest<br><br><br><br> The last one is 6.00 sec
    9·1 answer
  • To open a soda can lid, a force of 50 N is applied to a car key, which acts as a lever. If the car key applies a force of 400 N
    12·1 answer
  • To investigate how the vertical height and horizontal distance travelled by a table tennis ball is affected by the surface with
    13·1 answer
  • An elevator cabin has a mass of 358.1 ݇݃, and the combined mass of the people inside the cabin is 169.2 ݇݃. The cabin is puled u
    9·1 answer
  • The radius of a lead atom is 175 pm. how many lead atoms would have to be laid side by side to span a distance of 6.11 mm?
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!