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3 years ago

What effect will a turning point have on an individuals life

Physics

2 answers:

goldfiish [28.3K]3 years ago

7 0

Answer:

it will cause people to go a little bit crazy

Explanation:

ankoles [38]3 years ago

4 0

Answer:

The turning points are those instants, moments or situations that happen in an absolutely unexpected way, as a result of which your life changes ... and nothing is the same as before.

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What is the wavelength of an earthquake wave if it has a speed of 15 km/s and a frequency of 12 Hz?

Natasha2012 [34]

<h2>Answer: 1.25 km</h2>

Explanation:

The velocity $V$ of a wave is given by:

$V=\lambda.f$ (1)

Where:

$\lambda$ is the wavelength of the wave

$f$ is the frequency of the wave. Its unit is Hertz ( $1Hz=\frac{1}{s}$ )

So, we have to find $\lambda$ from equation (1):

$\lambda=\frac{V}{f}$ (2)

$\lambda=\frac{15km/s}{12Hz}$

Finally we obtain the wavelength of the earthquake wave:

$\lambda=1.25 km$

4 0

3 years ago

How do molecules at warm temperatures differ from molecules at cool temperatures? Question 1 options: At warm temperatures, mole

yaroslaw [1]

Answer:

A. At warm tempetures, molecules move around more.

Explanation:

I'm at k12 and I just took the test got it right. Physical Science: Unit 2 Test

7 0

3 years ago

Read 2 more answers

A radar station sends out a 250000 Hz sound wave at a speed of 340 m/s. The sound wave bounces off a weather ballon and returns

Eddi Din [679]

Answers:

a)The balloon is 68 m away of the radar station

b) The direction of the balloon is towards the radar station

Explanation:

We can solve this problem with the Doppler shift equation:

$f'=\frac{V+V_{o}}{V-V_{s}} f$ (1)

Where:

$f=250,000 Hz$ is the actual frequency of the sound wave

$f'=240,000 Hz$ is the "observed" frequency

$V=340 m/s$ is the velocity of sound

$V_{o}=0 m/s$ is the velocity of the observer, which is stationary

$V_{s}$ is the velocity of the source, which is the balloon

Isolating $V_{s}$ :

$V_{s}=\frac{V(f'-f)}{f'}$ (2)

$V_{s}=\frac{340 m/s(240,000 Hz-250,000 Hz)}{240,000 Hz}$ (3)

$V_{s}=-14.16 m/s$ (4) This is the velocity of the balloon, note the negative sign indicates the direction of motion of the balloon: It is moving towards the radar station.

Now that we have the velocity of the balloon (hence its speed, the positive value) and the time ( $t=4.8 s$ ) given as data, we can find the distance: