All categories

3 years ago

Anempt 1012 Find the mean for the given set of data. -4,-3,-1,-1, 0,1

Mathematics

2 answers:

WARRIOR [948]3 years ago

4 0

Answer:

-1 1/3

Step-by-step explanation:

To find the mean, add up all the numbers

(-4+-3+-1+-1+0+1) =

-8

Then divide by the number of terms

-8/6

-4/3

-1 1/3

igomit [66]3 years ago

3 0

Answer A is your answer

Step-by-step explanation:

You might be interested in

Would you like Brainliest?

IceJOKER [234]

Answer: yes please and thank you in advance :)

3 0

2 years ago

5 1/2+ 3 2/3+ 1 4/5

Mazyrski [523]

Answer:

$10\frac{29}{30}$

Step-by-step explanation:

$5\frac{1}{2} +3\frac{2}{3} +1\frac{4}{5}$

Let us group the integers and the fractions.

$5\frac{1}{2} +3\frac{2}{3} +1\frac{4}{5}$ = $(5+3+1)+(\frac{1}{2} +\frac{2}{3}+\frac{4}{5} )$

= $9+\frac{15+20+24}{30}$

$= 9+\frac{59}{30}$

$=9+1\frac{29}{30}$

$=10\frac{29}{30}$

7 0

3 years ago

A farmer has a field in the shape of a triangle. The farmer has asked the manufacturing class at your school to build a metal fe

Finger [1]

Answer:

Fencing required = 1586 m

Step-by-step explanation:

The given statements can be thought of a triangle $\triangle ABC$ as shown in the diagram attached.

A be the 1st vertex, B be the 2nd vertex and C be the 3rd vertex.

Distance between 1st and 2nd vertex, AB = 435 m

Distance between 2nd and 3rd vertex, AC = 656 m

$\angle A =49^\circ$

To find:

Fencing required for the triangular field.

Solution:

Here, we know two sides of a triangle and the angle between them.

To find the fencing or perimeter of the triangle, we need the third side.

Let us use Cosine Rule to find the third side.

Formula for cosine rule:

$cos A = \dfrac{b^{2}+c^{2}-a^{2}}{2bc}$

Where

a is the side opposite to $\angle A$

b is the side opposite to $\angle B$

c is the side opposite to $\angle C$

$\Rightarrow cos 49^\circ = \dfrac{656^{2}+435^{2}-BC^{2}}{2\times 435\times 656}\\\Rightarrow BC^2 = 430336+189225-2 (435)(656)cos49^\circ\\\Rightarrow BC^2 = 430336+189225-570720\times cos49^\circ\\\Rightarrow BC^2 =619561-570720\times cos49^\circ\\\Rightarrow BC \approx 495\ m$

Perimeter of the triangle = Sum of three sides = AB + BC + AC

Perimeter of the triangle = 435 + 495 + 656 = 1586 m

Fencing required = 1586 m

4 0

3 years ago

A toy company makes rectangular sandboxes that measure 6 feet by 5 feet by 1.2 feet. A customer buys a sandbox and 40 cubic feet

Iteru [2.4K]

Answer:

Customer has bought too much sand

Step-by-step explanation:

Given that the dimensions (Length, Width and Height) of rectangular box are = 6,5, 1.2.

Volume of a rectangular box = Length * Width * Height

=> 6*5*1.2

=> 36 cubic feet

As mentioned, customer bought a sand box and 40 cubic feet of sand.

So,

Volume of rectangular box (R) = 36 cubic feet

Volume of Sand (S) = 40 cubic feet

From analysis

S > R

Which shows that the capacity of sandbox is 36 cubic feet and volume is 40 feet that is a little greater than desired capacity.

Therefore, customer has bought too much sand.

4 0

3 years ago

I haven't done this in so long. I forgot how. Please help!

zhuklara [117]

B is the answer yesssss

6 0

3 years ago

Read 2 more answers