All categories

3 years ago

Anempt 1012 Find the mean for the given set of data. -4,-3,-1,-1, 0,1

Mathematics

2 answers:

WARRIOR [948]3 years ago

4 0

Answer:

-1 1/3

Step-by-step explanation:

To find the mean, add up all the numbers

(-4+-3+-1+-1+0+1) =

-8

Then divide by the number of terms

-8/6

-4/3

-1 1/3

igomit [66]3 years ago

3 0

Answer A is your answer

Step-by-step explanation:

You might be interested in

Given the function h(x) =1/3 |x-6| +4, evaluate the function when x = - 3, - 2, and 0

Masja [62]

|x| = x for x ≥ 0

examples:

|3| = 3; |0.56| = 0.56; |102| = 102

|x| = -x for x < 0

examples:

|-3| = -(-3) = 3; |-0.56| = -(-0.56) = 0.56; |-102| = 102

--------------------------------------------------------------------------------

Use PEMDAS:

P Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

--------------------------------------------------------------------------------

$h(x)=\dfrac{1}{3}|x-6|+4$

Put the values of x to the equation of the function h(x):

$x=-3\to h(-3)=\dfrac{1}{3}|-3-6|+4=\dfrac{1}{3}|-9|+4=\dfrac{1}{3}(9)+4=3+4=7\\\\x=-2\to h(-2)=\dfrac{1}{3}|-2-6|+4=\dfrac{1}{3}|-8|+4=\dfrac{1}{3}(8)+4=\dfrac{8}{3}+\dfrac{12}{3}=\dfrac{20}{3}\\\\x=0\to h(0)=\dfrac{1}{3}|0-6|+4=\dfrac{1}{3}|-6|+4=\dfrac{1}{3}(6)+4=2+4=6$

6 0

3 years ago

Determine the values of the constants b and c so that the function given below is differentiable. f(x)={2xbx2+cxx≤1x>1

Lera25 [3.4K]

Assuming the function is

$f(x)=\begin{cases}2x&\text{for }x\le1\\bx^2+cx&\text{for }x>1\end{cases}$

For $f(x)$ to be differentiable, it necessarily has to be continuous. For this condition to be met, we need

$\displaystyle\lim_{x\to1^-}f(x)=\lim_{x\to1^+}f(x)=f(1)$
$\iff\displaystyle\lim_{x\to1}2x=\lim_{x\to1}(bx^2+cx)$
$\iff2=b+c$

For the derivative to exist, the one-sided limits of the derivative must also exist and be equal. We have

$f'(x)=\begin{cases}2&\text{for }x1\end{cases}$

$\displaystyle\lim_{x\to1^-}2=\lim_{x\to1^+}(2bx+c)$
$\iff2=2b+c$

Now we solve for $b$ and $c$ :

$\begin{cases}b+c=2\\2b+c=2\end{cases}\implies b=0,c=2$

5 0

3 years ago

Which line is perpendicular to y = 2x -8

zlopas [31]

A- Perpendicular lines have negative reciprocal slopes. Therefore a perpendicular line to 2x-8 will have a slope of -1/2. Once solved in slope intercept form, choice A shows a line of slope -2/4, equivalent to -1/2

6 0

3 years ago

Read 2 more answers

Can someone help me with this ASAP?

ZanzabumX [31]

Answer: its an interrogative sentence

Step-by-step explanation:

4 0

3 years ago

Heather has to solve this system of equations using elimination. What should be her first step?

charle [14.2K]

I don’t know what the equation is but when using elimination you should cancel out opposite numbers such as 4x and negative 4x