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3 years ago

1.25 × 109 + 3.50 × 109 + 3.25 × 109 =

Mathematics

2 answers:

o-na [289]3 years ago

6 0

Answer: The answer is 872

Step-by-step explanation:

Nadusha1986 [10]3 years ago

5 0

Answer:

872 is the final answer

Step-by-step explanation:

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S641591 is a hacker don’t trust em

horrorfan [7]

Answer:

welp ok

Step-by-step explanation:

6 0

3 years ago

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Is linear equations algebra or pre-algebra??? And is "Collage and career ready math" higher than regular 8th grade math????

Zina [86]

I’m going to say pre-algebra because that’s when I learned it in my school system but you may also learn it in algebra as well, College ready math can start in 8th grade math but I would think it would be in highschool.

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3 years ago

Find the solution of the differential equation that satisfies the given initial condition. y' tan x = 3a + y, y(π/3) = 3a, 0 &lt

Paladinen [302]

Answer:

$y(x)=4a\sqrt{3}* sin(x)-3a$

Step-by-step explanation:

We have a separable equation, first let's rewrite the equation as:

$\frac{dy(x)}{dx} =\frac{3a+y}{tan(x)}$

But:

$\frac{1}{tan(x)} =cot(x)$

So:

$\frac{dy(x)}{dx} =cot(x)*(3a+y)$

Multiplying both sides by dx and dividing both sides by 3a+y:

$\frac{dy}{3a+y} =cot(x)dx$

Integrating both sides:

$\int\ \frac{dy}{3a+y} =\int\cot(x) \, dx$

Evaluating the integrals:

$log(3a+y)=log(sin(x))+C_1$

Where C1 is an arbitrary constant.

Solving for y:

$y(x)=-3a+e^{C_1} sin(x)$

$e^{C_1} =constant$

So:

$y(x)=C_1*sin(x)-3a$

Finally, let's evaluate the initial condition in order to find C1:

$y(\frac{\pi}{3} )=3a=C_1*sin(\frac{\pi}{3})-3a\\ 3a=C_1*\frac{\sqrt{3} }{2} -3a$

Solving for C1:

$C_1=4a\sqrt{3}$

Therefore:

$y(x)=4a\sqrt{3}* sin(x)-3a$

3 0

4 years ago

Which of these are the intercepts of the graph of y = 3x – 12?

charle [14.2K]

Y intercept is (0,-12), the x-intercept is (4,0)

5 0

4 years ago

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Graph the equation<br>y=x^2 -<br><img src="https://tex.z-dn.net/?f=y%20%3D%20x%5E%7B2%7D%20%20-%202" id="TexFormula1" title="y =

rusak2 [61]

Answer:

the graph is attached below

Step-by-step explanation:

$y=x^2 - 2$

LEts make a table to get the coordinates

we need to select integers between -3 and 3

x y=x^2 - 2

-2 y=(-2)^2-2=2 (-2,2)

0 y= (0)^2 - 2= -2 (0,-2)

2 y=(2)^2-2 = 2 (2,2)

Now we use the table for graphing the given equation

The graph is attached below

6 0

4 years ago