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2 years ago

Write the formula and name of the compound formed from the following ionic interactions:

Chemistry

1 answer:

nirvana33 [79]2 years ago

3 0

Answer:

Explanation:

a ) period 4 noble gas is krypton

isoelectronic with it are Sr ⁺² and Br⁻

compound is SrBr₂

b ) Period 3 noble gas is Argon

isoelectronic with it are Mg⁺² and O⁻²

compound is MgO

c) 2+ ion is the smallest with a filled d subshell is Zn⁺² , smallest halogen

is F⁻

compound is ZnF₂

d ) ions from the largest and smallest ionizable atoms in Period 2

Li⁺ and F⁻

compound is LiF

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A reaction between an acid and a base produced lithium chloride (LiCl). What acid and base combination could produce this salt?

erica [24]

Answer:

B. hydrochloric acid and lithium hydroxide

Explanation:

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2 years ago

What are groups 1, 2, and 3 examples of on the periodic table? A. Nonmetals B. Metals C. Noble gases D. Metalloids

tankabanditka [31]

The correct answer is:

Metals

They are all alkali and transition metals

Explanation:

The periodic table includes elements clustered into groups with comparable properties. Alkali metals are reactive, soft metals with low densities. Transition metals are unreactive metals that have many have common uses. Halogens are reactive non-metals that form glowing vapors.

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3 years ago

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If a helium filled ballon has a volume of 3.4l at 25°c and 1.18atm., what is its volume at STP?

vladimir2022 [97]

Answer:

3.711 L

Explanation:

The formula you need to use is the following:

$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\$

3.4L / 298 K = V2 / 273 K

V2 = 3.711 L

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2 years ago

Heat is transferred by conduction through a wall of thickness 0.87 m. What is the rate of heat transfer if the walls thermal con

erik [133]

Explanation:

The given data is as follows.

Thickness (dx) = 0.87 m, thermal conductivity (k) = 13 W/m-K

Surface area (A) = 5 $m^{2}$ , $T_{1} = 14^{o}C$

$T_{2} = 93^{o}C$

According to Fourier's law,

Q = $-kA \frac{dT}{dx}$

Hence, putting the given values into the above formula as follows.

Q = $-kA \frac{dT}{dx}$

= $-13 W/m-k \times 5 m^{2} \times \frac{(14 - 93)}{0.87 m}$

= 5902.298 W

Therefore, we can conclude that the rate of heat transfer is 5902.298 W.

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3 years ago

Which of the following hypotheses cannot be tested using the scientific method

Arturiano [62]

I believe it's answer #3. Logically, at least.

You can test #1 through trial and error.
You can experiment #2 also through trial and error.
You cannot test #3 through trial and error, because that would be catastrophic.
You can test #4 through a survey and individual study and data collection.

7 0

3 years ago

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