Answer:
You have to remember this memory aid, diagonals and all.
You have to keep a tight tally of the electrons you’ve used so far so you don’t go over the number of electrons in the element you’re working on.
You have to remember how many electrons fit into each subshell (s, p, d, f).
It takes a lot of time, especially when the element has more than 20 electrons.
Explanation:
Answer:
Empirical evidence for a proposition is evidence, i.e. what supports or counters this proposition, that is constituted by or accessible to sense experience or experimental procedure. Empirical evidence is of central importance to the sciences and plays a role in various other fields, like epistemology and law.
Explanation:
thanks me later
Answer:
The molecular formula of the compound is C₂H₄F₂ or CH₃CHF₂
Explanation:
From the question given above, the following data were obtained:
Empirical formula of the compound = CH₂F
Fórmula mass of compound = 66 g/mol
Molecular formula of the compound =?
The molecular formula of the compound can be obtained as follow:
Molecular formula = [Empirical formula]ₙ
Molecular formula = [CH₂F]ₙ
[CH₂F]ₙ = 66
[12 + (2×1) + 19] n = 66
[12 + 2+ 19]n = 66
33n = 66
Divide both side by 33
n = 66/33
n = 2
Molecular formula = [CH₂F]ₙ
Molecular formula = [CH₂F]₂
Molecular formula = C₂H₄F₂
Thus, the molecular formula of the compound is C₂H₄F₂ or CH₃CHF₂
Answer:
Explanation:
If one mole of carbon monoxide has a mass of 28.01 g and one mole of carbon dioxide has a mass of 44.01 g , it follows that the reaction produces 44.01 g of carbon dioxide for every 28.01 g of carbon monoxide.
S- and P-Block elements are known as Representative elements.
Groups 1-2 and Groups 13-18