(a) 5.66 m/s
The flow rate of the water in the pipe is given by

where
Q is the flow rate
A is the cross-sectional area of the pipe
v is the speed of the water
Here we have

the radius of the pipe is
r = 0.260 m
So the cross-sectional area is

So we can re-arrange the equation to find the speed of the water:

(b) 0.326 m
The flow rate along the pipe is conserved, so we can write:

where we have

and where
is the cross-sectional area of the pipe at the second point.
Solving for A2,

And finally we can find the radius of the pipe at that point:

The object will move if the forces are unbalanced.
Newtons second tells you that when a net force (the unbalanced force) is applied to and object it will produce an acceleration (movement) in direct proportion to the force and in inverse proportion to the mass of the object.
Answer:
Power = 50204 [watts]
Explanation:
We know that the power is defined by the following expression:
Power = Work/time
where:
Power [watts]
time [seconds]
The work done will be the following:
Work = Force * distance [Joules]
Force[Newtons]
distance[meters]
Force = mass* gravity
Force=290 [kg]*9.81[m/s^2] =2844.9[N]
Work = 2844.9[N]*300[m] = 853470[J]
Therefore
Power = 853470 / 17 = 50204 [watts]