Answer:
29.4 N/m
0.1
Explanation:
a) From the restoring Force we know that :
F_r = —k*x
the gravitational force :
F_g=mg
Where:
F_r is the restoring force .
F_g is the gravitational force
g is the acceleration of gravity
k is the constant force
xi , x2 are the displacement made by the two masses.
Givens:
<em>m1 = 1.29 kg</em>
<em>m2 = 0.3 kg </em>
<em>x1 = -0.75 m </em>
<em>x2 = -0.2 m </em>
<em>g = 9.8 m/s^2 </em>
Plugging known information to get :
F_r =F_g
-k*x1 + k*x2=m1*g-m2*g
k=29.4 N/m
b) To get the unloaded length 1:
l=x1-(F_1/k)
Givens:
m1 = 1.95kg , x1 = —0.75m
Plugging known infromation to get :
l= x1 — (F_1/k)
= 0.1
Answer:
81.8 m/s
Explanation:
The initial velocity of the plane is:
(toward east)
So, decomposing along the x- and y- directions:
(we took east as positive x-direction and north as positive y-direction)
The acceleration is
(northwest, so the angle with the positive x-direction is 135 degrees)
Decomposing it along the two directions:
So the two components of the velocity after a time t = 25.0 s will be
So, the magnitude of the velocity of the plane will be
I think that the answer is 13.386 inches.
The answer to the question is true
