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olya-2409 [2.1K]
3 years ago
10

A 4.0 kg object will have a weight of approximately 14.8 N on Mars. What is the gravitational field strength on M

Physics
1 answer:
Pie3 years ago
3 0

Answer:

Gravitational field strength =weight/mass

Explanation:

14.8N/4.0kg

3.7N/kg

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Which statement best describes the relationship between mass and gravitational attraction (pull)?
Gnesinka [82]

Answer:

The first option, "The more mass an object has, the greater the gravitational pull. "

Explanation:

Newton's Law of Gravity states that F_G=\frac{Gm_1m_2}{r^{2}}, where G is the gravitational constant, m_1 and m_2 are the masses of the two objects, and <em>r</em> is the distance between the objects' centers. Because the objects' masses are in the fraction's numerator, they are directly proportional to F_G, and increasing the mass of one or both objects increases the gravitational pull.

Please have a great day! I hope this helps you understand the question!

7 0
3 years ago
Esta Bien Hecho?<br> desde alli gracias
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Answer:yeah

Explanation:its good

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3 years ago
Read 2 more answers
A pendulum of mass 5.0 kg hangs in equilibrium. A frustrated student walks up to it and kicks the bob with a horizontal force of
Phoenix [80]

Answer:

The length is L = 6.206m and the angle is \theta = 37.752^o.

Explanation:

The period T of the pendulum is related to its length L by

T = 2\pi \sqrt{\dfrac{L}{g} },

where g =9.8m/s^2 is the acceleration due to gravity.

Solving for L we get

L = \dfrac{T^2g}{4\pi^2}

putting in T =5.0s and g =9.8m/s^2 we get:

L = \dfrac{(5.0s)^2*9.8m/s^2}{4\pi^2}

\boxed{L = 6.206m.}

There are two forces acting on the pendulum: The gravitational force mg and the F = 30N student's force. Therefore, the angular displacement \theta that these forces give is

sin(\theta ) = \dfrac{F}{mg}

\theta = sin^{-1}( \dfrac{F}{mg})

putting in F =30N, m =5.0kg, and g =9.8m/s^2 we get

\theta = sin^{-1}( \dfrac{30N}{5.0kg*9.8m/s^2})

\boxed{\theta = 37.752^o.}

4 0
4 years ago
Fresh water flows through a horizontal tapered pipe. At the wide end its speed is 8 m/s. The difference in pressure between the
a_sh-v [17]

Answer:

8.64 m/s

Explanation:

v1 = 8 m/s, v2 = ?, P2 - P1 = 5338 Pa, density of water, d = 1000 kg/m^3

By the use of Bernoulli's theorem

P 1 + 1/2 x d x v1^2 = P2 + 1/2 x d x v2^2

P2 - P1 = 1/2 x d x (v2^2 - v1^2)

5338 = 0.5 x 1000 x (v2^2 - 64)

10.676 = v2^2 - 64

v2^2 = 74.676

v2 = 8.64 m/s  

3 0
3 years ago
3) Principles of rectilinear proportion of light 9​
8_murik_8 [283]

Answer:Principle of rectilinear propagation of light

Explanation:Principle of rectilinear propagation of light

Rectilinear propagation of light refers to the propensity of light to travel along a straight line without any interference in its trajectory. ... It is because light travels along a straight line and leaves only the areas where the object interferes.

7 0
2 years ago
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