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2 years ago

A 4.0 kg object will have a weight of approximately 14.8 N on Mars. What is the gravitational field strength on M

Physics

1 answer:

Pie2 years ago

3 0

Answer:

Gravitational field strength =weight/mass

Explanation:

14.8N/4.0kg

3.7N/kg

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A block with m = 300 grams oscillates at the end of a linear spring with k = 6.5 N/m. (assume this is a top-down view and the bl

inna [77]

Answer:

a) T=1.35s

b) amplitude = 0.0923m

Explanation:

m=300 gr

k=6.5 N/m

first we need to get the angular frequency of the motion

so we have that

ω = √(k/m)

in this case motion is a simple harmonic so the period is defined by:

T= 2π / ω

T= 2π / √(k/m)

replacing the variables...

T= 2π / √(6.5/0.3)

T=1.35s (period of the block's motion)

and...

α max = | ω²r max |

2 = (2π/1.35)² * r max

r max= 0.0923m

6 0

3 years ago

An elevator filled with passengers has a mass of 1683 kg. (a) The elevator accelerates upward from rest at a rate of 1.20 m/s2 f

artcher [175]

Answer:

the tension is 18513N

Explanation:

Given that

mass = 1683kg

acceleration = 1.2m/s^2

acceleration due to gravity = 9.8m/s^2

T-mg = ma

T = ma + mg

T = m(a +g)

T = 1683 kg(1.20 m/s2 + 9.8)

T = 1683 (11)

T = 18513N

therefore, the tension is 18513N

4 0

3 years ago

Read 2 more answers

Can the distance coverd by a body ever be negative? What about its distance and displacement

Tju [1.3M]

answer in photo enjoy

4 0

2 years ago

A car of mass 1000 kg travelling at a velocity of 25 m/s collides with another car of mass 1500kg which is at rest. The two cars

Svetach [21]

Answer:

<em>The velocity of the two cars is 10 m/s after the collision.</em>

Explanation:

<u>Law Of Conservation Of Linear Momentum </u>

The total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and velocity v is

P=m.v

If we have a system of bodies, then the total momentum is the sum of them all

$P=m_1v_1+m_2v_2+...+m_nv_n$

If some collision occurs, the velocities change to v' and the final momentum is:

$P'=m_1v'_1+m_2v'_2+...+m_nv'_n$

In a system of two masses, the law of conservation of linear momentum takes the form:

$m_1v_1+m_2v_2=m_1v'_1+m_2v'_2$

If both masses stick together after the collision at a common speed v', then:

$m_1v_1+m_2v_2=(m_1+m_2)v'$

The car of mass m1=1000 Kg travels at v1=25 m/s and collides with another car of m2=1500 Kg which is at rest (v2=0).

Knowing both cars stick and move together after the collision, their velocity is found solving for v':

$\displaystyle v'=\frac{m_1v_1+m_2v_2}{m_1+m_2}$

$\displaystyle v'=\frac{1000*25+1500*0}{1000+1500}$

$\displaystyle v'=\frac{25000}{2500}$

v' = 10 m/s

The velocity of the two cars is 10 m/s after the collision.

4 0

3 years ago

A stone is dropped from the top a 45m hign building how fast will it moving when it reaches the ground? Ande what will its veloc

posledela

Answer:

29.7 m/s fast, velocity is 29.7 m/s

Explanation:

Applying,

v² = u²+2gs...................... Equation 1

Where v = final velocity, u = initial velocity, g = acceleration due to gravity, s = distance.

Given: u = 0 m/s (dropped from height), s = 45 m

Constant: g = 9.8 m/s²

Substitute these values into equation 1

v² = 0²+2×9.8×45

v² = 882

v = √(882)

v = 29.7 m/s.

Hence the stone will be moving 29.7 m/s fast and the velocity is also 29.7 m/s

7 0

2 years ago