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Igoryamba
4 years ago
5

a set of water travels at 10 m/s, and 5.0 waves pass you in 2.0s. what is the wavelength of the waves?

Physics
1 answer:
Alecsey [184]4 years ago
3 0
Well, I think the answer would be 4 meters because the speed is in meters per second and the frequency is 5 waves every 2 seconds. 
Wavelength = Speed/Frequency
I think the frequency is 2.5 waves a second but that's not something I'm 100% sure about.
I hope this helps though.
You might be interested in
Anyone know how to do this?
Gala2k [10]

Answer:

I think, (remember think) it might be 2.0 m/s

Explanation:

If it's wrong I'm truly sorry.

6 0
3 years ago
A bullet is fired with a muzzle velocity of 1178 ft/sec from a gun aimed at an angle of 26° above the horizontal. Find the horiz
dalvyx [7]

Answer:

1058.78 ft/sec

Explanation:

Horizontal Component of Velocity; This is the velocity of a body that act on the horizontal axis. I.e Velocity along x-axis

The horizontal velocity of a body can be calculated as shown below.\

Vh = Vcos∅.......................... Equation 1

Where Vh = horizontal component of the velocity, V = The velocity acting between the horizontal and the vertical axis, ∅ = Angle the velocity make with the horizontal.

Given: V = 1178 ft/sec, ∅ = 26°

Substitute into equation 1

Vh = 1178cos26

Vh = 1178(0.8988)

Vh = 1058.78 ft/sec

Hence the horizontal component of the velocity = 1058.78 ft/sec

8 0
3 years ago
The force of gas particles against the walls of a container is called ________
Liono4ka [1.6K]

Answer:

the answer is pressure

8 0
3 years ago
If a rock climber accidentally drops a 52.5-g piton from a height of 325 meters, what would its speed be just before striking th
alex41 [277]
Ignoring air resistance, the Kinetic energy before hitting the ground will be equal to the potential energy of the Piton at the top of the rock.  
So we have 1/2 MV^2 = MGH 
V^2 = 2GH 
V = âš2GH 
V = âš( 2 * 9.8 * 325)  
V = âš 6370
 V = 79.81 m/s
6 0
3 years ago
Compare the collision between two baseballs and a catcher's mitt.
Nookie1986 [14]

The applied force is different for the two cases

The case A with a greater force involves the greatest momentum change

The case A involves the greatest force.

<h3>What is collision?</h3>
  • This is the head-on impact between two object moving in opposite or same direction.

The initial momentum of the two ball is the same.

P = mv

where;

  • m is the mass of each
  • v is the initial velocity of each ball

Since the force applied by the arm is different, the final velocity of the balls before stopping will be different.

Thus, the final momentum of each ball will be different

The impulse experienced by each ball is different since impulse is the change in momentum of the balls.

J = ΔP

The force applied by the rigid arm is greater than the force applied by the relaxed arm because the force applied by the rigid arm will cause the ball to be brought to rest faster.

Thus, we can conclude the following;

  • The applied force is different for the two cases
  • The case A with a greater force involves the greatest momentum change
  • The case A involves the greatest force.

Learn more about impulse here: brainly.com/question/25700778

3 0
3 years ago
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