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oee [108]
4 years ago
15

A student is studying the fossils of a plant species that lived several million years ago. The fossils of this species are found

in Australia and Antarctica.Which statement is the MOST LIKELY explanation for why fossils of this plant are found on these two continents? *
Physics
1 answer:
tresset_1 [31]4 years ago
6 0

B. Australia and Antarctica were a single landmass in the past.

Explanation:

The most likely explanation for why the fossils of this plant are found on these two continents is that Australia and Antarctica were a single landmass in the past.

This evidence is vastly supported by the theory of plate tectonics originally, the theory of continental drift.

  • Plate tectonics proposes that all land masses were once joined together as a single supercontinent called Pangaea.
  • The region of Antartica and Australia were once joined as a single continental mass.
  • The plant must have developed together at that time.
  • When the continents moved apart, they still had the fossils.

learn more:

Continental drift brainly.com/question/5002949

#learnwithBrainly

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A charge of -3.40 nC is placed at the origin of an xy-coordinate system, and a charge of 2.45 nC is placed on the y axis at y =
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Answer:

The magnitude of this force is 1.866\times10^{-4}\ N

The direction of this force is 55.69°.

Explanation:

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F_{13}=\dfrac{9\times10^{9}\times(-3.40\times10^{-9})\times5.00\times10^{-9}}{(2.90\times10^{-2})^2}

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Using formula of force

F_{12}=\dfrac{kq_{1}q_{2}}{r^2}

Put the value into the formula

F_{12}=\dfrac{9\times10^{9}\times(-3.40\times10^{-9})\times2.45\times10^{-9}}{(4.25\times10^{-2})^2}

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F=\sqrt{F_{13}^2+F_{12}^2+2F_{13}F_{12}\cos \theta}

Here, \theta=90

F=\sqrt{F_{13}^2+F_{12}^2}

Put the value into the formula

F=\sqrt{(-1.82\times10^{-4})^2+(-4.15\times10^{-5})^2}

F=0.0001866\ N

F=1.866\times10^{-4}\ N

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Using formula of direction

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Put the value into the formula

\theta=\tan^{-1}(\dfrac{4.25}{2.90})

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Hence, The magnitude of this force is 1.866\times10^{-4}\ N

The direction of this force is 55.69°.

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