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3 years ago

A solution, such as pure water, with a pH of 7 contains which of the following?

Chemistry

1 answer:

Butoxors [25]3 years ago

8 0

Answer:

Explanation:

Pure water always has equal concentrations of hydrogen and hydroxide ions.

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What is the maximum amount of electrons that can be in the third energy level of an atom? (question continued in comments)

Alex787 [66]

Answer:

18 electrons

Explanation:

If you search on Google you get the same answer, so the question gives you your answer.

6 0

4 years ago

Calculate the mass of an object that has a density of 3.52g/cm^3 and

valkas [14]

Answer:

17.6kg

Explanation:

mass = Volume × Density

mass = 5000cm^3 × 3.52g/cm^3

mass = 17600g = 17.6kg

3 0

3 years ago

What are the properties of the aluminum in the can

arlik [135]

Solid, malleable, and can be crushed

3 0

4 years ago

Write balanced net ionic equations and the corresponding equilibrium equations for the stepwise dissociation of the triprotic ac

Elza [17]

Answer:

$H_3PO_4(aq)+H_2O(l)\rightleftharpoons H_3O^+(aq)+H_2PO_4^{-}(aq); \ Ka_1$

$H_2PO_4^{-}(aq)+H_2O(l)\rightleftharpoons H_3O^+(aq)+HPO_4^{-2}(aq); \ Ka_2$

$HPO_4^{-2}(aq)+H_2O(l)\rightleftharpoons H_3O^+(aq)+PO_4^{-3}(aq); \ Ka_3$

Explanation:

Hello!

In this case, since the phosphoric acid is a triprotic acid, we infer it has three stepwise ionization reactions in which one hydrogen ion is released at each step, considering they are undergone due to the presence of water, thus, we proceed as follows:

$H_3PO_4(aq)+H_2O(l)\rightleftharpoons H_3O^+(aq)+H_2PO_4^{-}(aq); \ Ka_1$

$H_2PO_4^{-}(aq)+H_2O(l)\rightleftharpoons H_3O^+(aq)+HPO_4^{-2}(aq); \ Ka_2$

$HPO_4^{-2}(aq)+H_2O(l)\rightleftharpoons H_3O^+(aq)+PO_4^{-3}(aq); \ Ka_3$

Moreover, notice each step has a different acid dissociation constant, which are quantified in the following order:

Ka1 > Ka2 > Ka3

Best regards!

3 0

3 years ago

What volume will 1.25 liters of carbon dioxide occupy at 50.0°C if the pressure changes from 0.865 atm to 0.820 atm?

Elena-2011 [213]

To solve this we assume that the gas inside the balloon is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant temperature and number of moles of the gas the product of PV is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

P1V1 = P2V2

V2 = P1V1 / P2

V2 = 0.865 x 1.25 / 0.820

V2 = 1.32 L

6 0

4 years ago