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Alik [6]
3 years ago
13

Jshsmsnsksskjs landmarks sksnsn

Mathematics
1 answer:
Dima020 [189]3 years ago
5 0

Answer:

sknsonsknsknsknskdnksndksn?

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If the Diameter is ten then what is the area of it
Pepsi [2]

Answer:

78.54

Step-by-step explanation:

Hope this helps!

7 0
2 years ago
Find the volume of the prism.
Zigmanuir [339]

Answer:

The correct answer is first option.  270 m³

Step-by-step explanation:

Formula:

Volume of prism = Base area * Height

Area of triangle = bh/2  where b - base and h - height

From the figure we can see that height of prism = 36 m

Base is a right angled triangle with base 5 m and height = 3 m

<u>To find the Base area</u>

Area of triangle = bh/2 = (3 * 5)/2 = 15/2 = 7.5

<u>To find the volume of prism</u>

Volume = Base area * height = 7.5 * 36 = 270 m³

Therefore the correct answer is first option . 270 m³

7 0
3 years ago
Read 2 more answers
Will mark BRAINLIEST if you help
nlexa [21]
The first box is -7 and the other one is just 7
7 0
2 years ago
Read 2 more answers
What is the expression to find the distance between the points A and T
navik [9.2K]

Answer:

<h2>9</h2>

Step-by-step explanation:

The <u>square root </u>of

d=(x2​−x1​)^2+(y2​−y1​)^2​

A=(2,5) coordinates 1

T=(5,5) coordinates 2

So we put (5-2)^2 plus (5-5)^2

(3)^2+(0)^2

9+0

9

<h3><u>Brainliest please!</u></h3>
6 0
3 years ago
Find S12 for geometric series: (-7.5) + 15 + (-30) + ...
kolezko [41]

Answer:

S12 for geometric series: (-7.5) + 15 + (-30) + ... would be: 10237.5

Step-by-step explanation:

Given the sequence to find the sum up-to 12 terms

(-7.5) + 15 + (-30) + ...

As we know that

A geometric sequence has a constant ratio 'r' and is defined by

a_n=a_1\cdot r^{n-1}

\mathrm{Compute\:the\:ratios\:of\:all\:the\:adjacent\:terms}:\quad \:r=\frac{a_{n+1}}{a_n}

\frac{15}{\left(-7.5\right)}=-2,\:\quad \frac{\left(-30\right)}{15}=-2

\mathrm{The\:ratio\:of\:all\:the\:adjacent\:terms\:is\:the\:same\:and\:equal\:to}

r=-2

\mathrm{The\:first\:element\:of\:the\:sequence\:is}

a_1=\left(-7.5\right)

a_n=a_1\cdot r^{n-1}

\mathrm{Therefore,\:the\:}n\mathrm{th\:term\:is\:computed\:by}\:

a_n=\left(-7.5\right)\left(-2\right)^{n-1}

a_n=-\left(-2\right)^{n-1}\cdot \:7.5

\mathrm{Geometric\:sequence\:sum\:formula:}

a_1\frac{1-r^n}{1-r}

\mathrm{Plug\:in\:the\:values:}

n=12,\:\spacea_1=\left(-7.5\right),\:\spacer=-2

  =\left(-7.5\right)\frac{1-\left(-2\right)^{12}}{1-\left(-2\right)}

  =-7.5\cdot \frac{1-\left(-2\right)^{12}}{1+2}

\mathrm{Multiply\:fractions}:\quad \:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c}

  =-\frac{-30712.5}{1+2}          ∵  \left(1-\left(-2\right)^{12}\right)\cdot \:7.5=-30712.5

 =-\frac{-30712.5}{3}

 =\frac{30712.5}{3}

 =10237.5

Thus, S12 for geometric series: (-7.5) + 15 + (-30) + ... would be: 10237.5        

5 0
3 years ago
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