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Alik [6]
3 years ago
13

Jshsmsnsksskjs landmarks sksnsn

Mathematics
1 answer:
Dima020 [189]3 years ago
5 0

Answer:

sknsonsknsknsknskdnksndksn?

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write an equation of the line with the following information. Through (4,1) and perpendicular to y=1/3x +3
Yakvenalex [24]
Perpendicular means the two lines' slopes are negative reciprocal to each other. the slope of the given line is 1/3, therefore the slope of the perpendicular line is -3/1, which is -3
use the point-slope form: the given point is (4,1), so (y-1)=-3(x-4)
you can stop right here or you can write it into slope intercept form:
y-1=-3x+12
y=-3x+13
5 0
3 years ago
The eccentricity e of an ellipse is defined as the number c/a, where a is the distance of a vertex from the center and c is the
Anna71 [15]

Answer:

Check below, please.

Step-by-step explanation:

Hi, there!

Since we can describe eccentricity as e=\frac{c}{a}

a) Eccentricity close to 0

An ellipsis with eccentricity whose value is 0, is in fact, a degenerate one almost a circle. An ellipse whose value is close to zero is almost a degenerate circle. The closer the eccentricity comes to zero, the more rounded gets the ellipse just like a circle. (Check picture, please)

\frac{x^2}{a^2} +\frac{y^2}{b^2} =1 \:(Ellipse \:formula)\\a^2=b^2+c^2 \: (Pythagorean\: Theorem)\:a=longer \:axis.\:b=shorter \:axis)\\a^2=b^2+(0)^2 \:(c\:is \:the\: distance \: the\: Foci)\\\\a^2=b^2 \\a=b\: (the \:halves \:of \:each\:axes \:measure \:the \:same)

b) Eccentricity =5

5=\frac{c}{a} \:c=5a

An eccentricity equal to 5 implies that the distance between the Foci has to be five (5) times larger than the half of its longer axis! In this case, there can't be an ellipse since the eccentricity must be between 0 and 1 in other words:

If\:e=\frac{c}{a} \:then\:c>0 , and\: c>0 \:then \:1>e>0

c) Eccentricity close to 1

In this case, the eccentricity close or equal to 1 We must conceive an ellipse whose measure for the half of the longer axis a and the distance between the Foci 'c' they both have the same size.

a=c\\\\a^2=b^2+c^2\:(In \:the\:Pythagorean\:Theorem\: we \:should\:conceive \:b=0)

Then:\\\\a=c\\e=\frac{c}{a}\therefore e=1

7 0
2 years ago
Which of the following illustrates the truth value of the given conditional statement?
garri49 [273]

Answer:

TT➪T

Step-by-step explanation:

8 0
2 years ago
Differentiate <br> \[\ln \sin^2 x\]
iragen [17]
Y = ln {[sin(x)]^2}

use the chain rule

y' = 1 /[sin(x)]^2 * 2sin(x)*cos(x) = 2cos(x) / sin(x) = 2 cot(x)

Answer: 2 cot(x)


7 0
3 years ago
Write the​ point-slope form of the line satisfying the given conditions. Then use the​ point-slope form of the equation to write
abruzzese [7]

slope = m = 16-10 / 8-5 = 6/3 = 2

y - y1 = m x (x-x1)

y-10 = 2 x (x-5)

y-10 = 2x-10

y = 2x


7 0
3 years ago
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