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Alik [6]
3 years ago
13

Jshsmsnsksskjs landmarks sksnsn

Mathematics
1 answer:
Dima020 [189]3 years ago
5 0

Answer:

sknsonsknsknsknskdnksndksn?

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A man bought 8 boxes highlighters, each with 24 highlighter pens inside, for $9 each box. He sold the highlighters for $1 each.
Katarina [22]

Answer:

The man earned money:

Step-by-step explanation:

$1 x 24 pieces =$24 revenue per box

$24 - $9 = $15 earning per box

$15 x 8 boxes = $120 total earnings

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Question 5<br> 60% of 50<br><br> Question 6<br> 25% of 16
musickatia [10]
Question 5 answer: 30

Question 6 answer: 4
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8 ten thousands 4 thousands 3 hundreds 6 tens 7 ones in Standard form
abruzzese [7]
80,000+4,000+300+60+7

84,367

The standard form is 84,367.

Hope this helps!
6 0
3 years ago
Which of the numbers listed below are solutions to the equation? Check all
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The answer is 25 and -25 :)

If this was helpful, please consider giving brainliest!

6 0
3 years ago
The following data represent the pH of rain for a random sample of 12 rain dates in Tucker County, West Virginia. A normal proba
Sphinxa [80]

Answer:

Step-by-step explanation:

n = 12

Mean = (4.58 + 5.72 + 4.77 + 4.76 + 5.19 + 5.05 + 4.80 + 4.77 + 4.75 + 5.02 + 4.74 + 4.56)/12 = 4.8925

Standard deviation = √(summation(x - mean)²/n

Summation(x - mean)² = (4.58 - 4.8925)^2 + (5.72 - 4.8925)^2 + (4.77 - 4.8925)^2 + (4.76 - 4.8925)^2 + (5.19 - 4.8925)^2 + (5.05 - 4.8925)^2 + (4.80 - 4.8925)^2 + (4.77 - 4.8925)^2 + (4.75 - 4.8925)^2 + (5.02 - 4.8925)^2 + (4.74 - 4.8925)^2 + (4.56 - 4.8925)^2 = 1.122225

Standard deviation = √(1.122225/12

s = 0.31

a) Point estimate = sample mean = 4.8925

Confidence interval is written in the form,

(Sample mean - margin of error, sample mean + margin of error)

Margin of error = z × s/√n

Where

From the information given, the population standard deviation is unknown and the sample size is small, hence, we would use the t distribution to find the z score

In order to use the t distribution, we would determine the degree of freedom, df for the sample.

df = n - 1 = 12 - 1 = 11

b) Since confidence level = 95% = 0.95, α = 1 - CL = 1 – 0.95 = 0.05

α/2 = 0.05/2 = 0.025

the area to the right of z0.025 is 0.025 and the area to the left of z0.025 is 1 - 0.025 = 0.975

Looking at the t distribution table,

z = 2.201

Margin of error = 2.201 × 0.31/√12

= 0.197

95% confidence interval = 4.8925 ± 0.197

Upper limit = 4.8925 + 0.197 = 5.0895

Lower limit = 4.8925 - 0.197 = 4.6955

We are 95% confident that the population mean of the rain water ph lies between 4.6955 and 5.0895

c) For 99% confidence level, z = 3.106

Margin of error = 3.106 × 0.31/√12

= 0.278

99% confidence interval = 4.8925 ± 0.278

Upper limit = 4.8925 + 0.278 = 5.1705

Lower limit = 4.8925 - 0.278 = 4.6145

We are 99% confident that the population mean of the rain water ph lies between 4.6145 and 5.1705

d) The interval gets wider as the confidence level is increased. This is logical since the test score is higher for 99% and therefore, increases the range of values. Since we want to be more confident, the range of values must be extended.

3 0
3 years ago
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