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Tema [17]
2 years ago
12

John bought a crate of floor tiles $100. The crate had 5 boxes of floor tiles. Each box contained 40 floor tiles. What is the co

st per tile ?
Mathematics
2 answers:
Aneli [31]2 years ago
6 0
Each tile would be 50 cents explanation: 40 multiplied by 5 is 200, 100 dollars divided by 200 tiles equals out to be 50 cents a piece :)
mash [69]2 years ago
4 0
$0.50.
There are a total of 200 tiles (5 x 40)
since John paid $100 for the 200 tiles,
We have to do $100 divided by 200.
Which is .5
So $.50
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Simplify 4sqrt(6) / sqrt(30) by rationalizing the denominator.
daser333 [38]
Given question is 4√6/√30
by rationalizing the denominator
4√6x√30/√30x√30
= 4√6x30/√30²
=4x√180/30 (i)
by solving the √180
√180=6√5
putting the value of √180 in (i)
=4x6√5/30
=24√5/30
=4√5/5 is the right answer.
8 0
3 years ago
Read 2 more answers
Consider the geometric sequence below.
vladimir1956 [14]

Answer:

f(1) = 8

Common ratio: 0.5

Step-by-step explanation:

f(1) means the firs term in a sequence.

In the function f(n), represented by 8, 4, 2, 1, .., the first term is 8.

f(1) = 8

To find the common ratio, divide any term by the term before it.

We can use any two of the given terms in the sequence EXCEPT for 8 because it is the first term and does not have a term before it.

I choose to divide the second term by the first term:

4/8 = 1/2 = 0.5

3 0
3 years ago
135<br> -----<br> 60<br><br> 25<br> ------<br> 8<br><br> 3125<br> -----------<br> 10000
katrin2010 [14]

Answer: If you are trying to put the fractions in simplest form, then here are your answers:

9/4

25/8

5/16

7 0
3 years ago
Grade 7 students were surveyed to determine how many hours a day they spent on various activities. The results are shown in the
Ghella [55]

Answer:

C) 118.8; 28.8

Step-by-step explanation:

for eating, it didn't make sense for it to be 288 degrees, so i eliminated the two off the list. For sleeping, it made more sense for it to be a 118.8 degree angle, so I narrowed it down to C.

5 0
3 years ago
The mean number of words per minute (WPM) read by sixth graders is 8888 with a standard deviation of 1414 WPM. If 137137 sixth g
Bingel [31]

Noticing that there is a pattern of repetition in the question (the numbers are repeated twice), we are assuming that the mean number of words per minute is 88, the standard deviation is of 14 WPM, as well as the number of sixth graders is 137, and that there is a need to estimate the probability that the sample mean would be greater than 89.87.

Answer:

"The probability that the sample mean would be greater than 89.87 WPM" is about \\ P(z>1.56) = 0.0594.

Step-by-step explanation:

This is a problem of the <em>distribution of sample means</em>. Roughly speaking, we have the probability distribution of samples obtained from the same population. Each sample mean is an estimation of the population mean, and we know that this distribution behaves <em>normally</em> for samples sizes equal or greater than 30 \\ n \geq 30. Mathematically

\\ \overline{X} \sim N(\mu, \frac{\sigma}{\sqrt{n}}) [1]

In words, the latter distribution has a mean that equals the population mean, and a standard deviation that also equals the population standard deviation divided by the square root of the sample size.

Moreover, we know that the variable Z follows a <em>normal standard distribution</em>, i.e., a normal distribution that has a population mean \\ \mu = 0 and a population standard deviation \\ \sigma = 1.

\\ Z = \frac{\overline{X} - \mu}{\frac{\sigma}{\sqrt{n}}} [2]

From the question, we know that

  • The population mean is \\ \mu = 88 WPM
  • The population standard deviation is \\ \sigma = 14 WPM

We also know the size of the sample for this case: \\ n = 137 sixth graders.

We need to estimate the probability that a sample mean being greater than \\ \overline{X} = 89.87 WPM in the <em>distribution of sample means</em>. We can use the formula [2] to find this question.

The probability that the sample mean would be greater than 89.87 WPM

\\ Z = \frac{\overline{X} - \mu}{\frac{\sigma}{\sqrt{n}}}

\\ Z = \frac{89.87 - 88}{\frac{14}{\sqrt{137}}}

\\ Z = \frac{1.87}{\frac{14}{\sqrt{137}}}

\\ Z = 1.5634 \approx 1.56

This is a <em>standardized value </em> and it tells us that the sample with mean 89.87 is 1.56<em> standard deviations</em> <em>above</em> the mean of the sampling distribution.

We can consult the probability of P(z<1.56) in any <em>cumulative</em> <em>standard normal table</em> available in Statistics books or on the Internet. Of course, this probability is the same that \\ P(\overline{X} < 89.87). Then

\\ P(z

However, we are looking for P(z>1.56), which is the <em>complement probability</em> of the previous probability. Therefore

\\ P(z>1.56) = 1 - P(z

\\ P(z>1.56) = P(\overline{X}>89.87) = 0.0594

Thus, "The probability that the sample mean would be greater than 89.87 WPM" is about \\ P(z>1.56) = 0.0594.

5 0
3 years ago
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