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GuDViN [60]
3 years ago
13

Ashik claims that the graph on the right is the correct interpretation of the scatterplot, but his friend Shelby claims that the

graph on the left is correct.
Shelby’s Graph Ashik’s Graph
A graph titled Shelby's Graph has points that form a curved line. A line with negative slope is drawn. A graph titled Ashik's Graph has points that form a curved line. A curved line is drawn to connect the points.

Who is correct and why?
Shelby is correct because the line of best fit has a negative slope and the trend shows a decrease in y values as the x values increase.
Shelby is correct because the line of best fit matches the points as closely as possible with a weak correlation.
Ashik is correct because the points are a strong correlation to this nonlinear association.
Ashik is correct because points with a weak correlation can never have linear association.
Mathematics
2 answers:
faltersainse [42]3 years ago
8 0

Answer:

The correct answer is C

Step-by-step explanation:

just took the test and got a 100.... btw i kinda need Brainliest to move to the next level can u help?

Edge 2021

Gnoma [55]3 years ago
4 0

Answer:

It’s B

Step-by-step explanation:

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Step-by-step explanation:

19/8 - d/4 - e/4

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3 years ago
g Gravel is being dumped from a conveyor belt at a rate of 10 ft3/min, and its coarseness is such that it forms a pile in the sh
Maslowich

Answer:

0.3537 feet per minute.

Step-by-step explanation:

Gravel is being dumped from a conveyor belt at a rate of 10 ft3/min. Since we are told that the shape formed is a cone, the rate of change of the volume of the cone.

\dfrac{dV}{dt}=10$ ft^3/min

\text{Volume of a cone}=\dfrac{1}{3}\pi r^2 h

If the Base Diameter = Height of the Cone

The radius of the Cone = h/2

Therefore,

\text{Volume of the cone}=\dfrac{\pi h}{3} (\dfrac{h}{2}) ^2 \\V=\dfrac{\pi h^3}{12}

\text{Rate of Change of the Volume}, \dfrac{dV}{dt}=\dfrac{3\pi h^2}{12}\dfrac{dh}{dt}

Therefore: \dfrac{3\pi h^2}{12}\dfrac{dh}{dt}=10

We want to determine how fast is the height of the pile is increasing when the pile is 6 feet high.

When h=6$ feet$\\\dfrac{3\pi *6^2}{12}\dfrac{dh}{dt}=10\\9\pi \dfrac{dh}{dt}=10\\ \dfrac{dh}{dt}= \dfrac{10}{9\pi}\\ \dfrac{dh}{dt}=0.3537$ feet per minute

When the pile is 6 feet high, the height of the pile is increasing at a rate of 0.3537 feet per minute.

7 0
4 years ago
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