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Mekhanik [1.2K]
3 years ago
5

You have 5 blocks of cheese. If it takes 2/3 block of cheese to make a pizza, how many pizzas can you make with 5 blocks of chee

se?
Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
5 0

Answer:

12

Step-by-step explanation:

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First question: 0

Second question: 0.94
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1. Write your answer using only<br> positive exponents.<br><br> (3ab^3c^-1)^3
marishachu [46]

Answer:

(\frac{{3ab^{3}}}{c^{1}} )^{3}

Step-by-step explanation:

(3ab^{3} c^{-1} )^{3} =(\frac{{3ab^{3}}}{c^{1}} )^{3}

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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
Nikitich [7]

Answer:   B. (-4, 0)

<u>Step-by-step explanation:</u>

The question is: when is the <u>function</u> constant?

function is also called f(x), which is also called "y".

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the y-value is constant (not increasing or decreasing) between x = -4 and x = 0. So the interval is (-4, 0)

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Help on #6 (an explanation would be great)
Gala2k [10]

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− 7 i \sqrt{2}

Step-by-step explanation:

5 0
3 years ago
The product of $7d^2-3d+g$ and $3d^2+hd-8$ is $21d^4-44d^3-35d^2+14d-16$. What is $g+h$?
galina1969 [7]
<h2>Answer:</h2><h2>g = 2  and h = -5</h2>

Step-by-step explanation:

To find the product with unknown values of variables, multiply the terms and equate the value to the given product.

(7d^{2} - 3d + g)(3d^{2} + hd - 8) = 21d^{4}  + 7hd^{3} - 56d^{2} - 9d^{3} - 3hd^{2} + 24d + 3gd^{2} + ghd - 8g

(7d^{2} - 3d + g)(3d^{2} + hd - 8)     = 21d^{4}  + (7h-9) d^{3} + (3g-56-3h)d^{2}  + (24+gh)d -8g   ... (1)

Comparing eq(1) to the product given in question,

-8g = -1

g = 2

24 + gh = 14, sub g =2,

24 + 2h = 14

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3 0
3 years ago
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