If you factor the denominator of the left multiplicand...
[(a-4)(a+3)]/[a(a-4)] you can see that the (a-4)s cancel out leaving:
(a+3)/a
now you have
(a+3)/a * 2a^3/((a+3)(a-1)) so the (a+3)s cancel out leaving:
1/a * 2a^3/(a-1) which is:
2a^3/(a(a-1)) so now a^1 cancel leaving
2a^2/(a-1)
Alright, let get started.
Kyle has a storage box having dimensions 2 ft long, 3 ft high and volume 12 cubic feet.
The formula for volume is = 
Suppose the width is w so,
Dividing by 6 in both sides
w = 2 feet
Myla has a storage box that is 4 ft high and 2 feet long and volume 16 cubic feet.
Suppose the width is w hence
Dividing 8 in both sides
w = 2 feet
Hence the width of Kyle and Myla's boxes, both are 2 feet. : Answer
Hope it will help :)
Let after n week both tanks have same quantity of water .
for first tank
=============
tank hold 540 gallon of water ,
leaking of water 4 gallon /week
so, in n week water leak from the tank =4× n = 4n
now, after n week quantity of water in the tank = 540 -4n
for second tank
==============
quantity of water in the tank =720 gallon
leaking of water at the rate = 7gallon/week
so, after n week water leak from the tank = 7× n =7n
after n week quantity of water rest in the tank = 720 -7n
now ,
according to question ,
water in first tank = water in second tank
540 -4n = 720 -7n
7n -4n = 720 -540
3n = 180
n = 60
hence , after 60 week both tank have same quantity of water.
