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Lubov Fominskaja [6]

2 years ago

7

hey so I just want to tell you all that you are amazing, beautiful (or handsome), and don't let anyone tell you otherwise. I why

I'm doing this but I just feel like we should remind each other about this every once in a while. have an amazing day and remember this.

1 answer:

valina [46]2 years ago

6 0

And always remember this applies to you too like honestly you’re amazing for doing this

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Please help me I will give brainliest

Rus_ich [418]

Answer:

60 milligrams

Step-by-step explanation:

just cross multiply! percentages are just fractions of 100. so you can say that $\frac{45}{x} =\frac{75}{100}$

multiple 75 by x and 45 by 100 and you get

4500=75x

divide both sides by 75 and you get 60

7 0

2 years ago

The weight of an object on Earth varies directly as the weight of the same object on the moon. A 300 pound object on Earth would

slava [35]

Answer: 12 pounds.

Step-by-step explanation:

To solve this question, we'll use the direct proportion which is.

y = kx

Where,

y = weight on moon = 48 pounds

x = weight on Earth = 300 pounds

k = Unknown

y = kx

48 = 300k

k = 48/300

k = 0.16

The weight that a 75 pound object on Earth would weigh on the moon will be:

y = kx

where,

y = weight on moon = Unknown

k = 0.16

x = weight on Earth = 75 pounds

y = kx

y= 0.16 × 75

y = 12 pounds

The weight on the moon will be 12 pounds.

7 0

3 years ago

Answer???? Angle 1, and angle 2. I need help

REY [17]

M> 1 + m>2 = 90°
x-12 + 5x = 90°
6x - 12 = 90°
6x -12 +12 = 90°+12
6x = 102
6x/6 = 102/6
x = 17

m>1 = x-12
m>1 = 17-12
m>1 = 5

m>2 = 5x
m>2 = 5(17)
m>2 = 85

7 0

2 years ago

Please help with this question please

puteri [66]

Answer:

Choice A

Step-by-step explanation:

(4m^5n^2/m^2n)^3

dividing exponents = subtraction

(4m^3n)^3

4^3 = 64

(m^3 )^3 = m^3x3 = m^9

64m^9n^3

5 0

3 years ago

A batch consists of 12 defective coils and 88 good ones. Find the probability of getting two good coils when two coils are rando

Allushta [10]

<u>Answer:</u>

The probability of getting two good coils when two coils are randomly selected if the first selection is replaced before the second is made is 0.7744

<u>Solution:</u>

Total number of coils = number of good coils + defective coils = 88 + 12 = 100

p(getting two good coils for two selection) = p( getting 2 good coils for first selection ) $\times$ p(getting 2 good coils for second selection)

p(first selection) = p(second selection) = $\frac{\text { number of good coils }}{\text { total number of coils }}$

Hence, p(getting 2 good coil for two selection) = $\frac{88}{100} \times \frac{88}{100} =\bold{0.7744}$

5 0

2 years ago