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Zinaida [17]
3 years ago
12

How do you write 6x (to the 3rd power) -60x (to the 2nd power) +144x in factored form?

Mathematics
1 answer:
docker41 [41]3 years ago
5 0

Answer:

<h2>6x(x-4)(x-6)</h2>

Step-by-step explanation:

I assume your expression is:

6x^3-60x^2+144x.

I'll use that information.

Factor 6x^3−60x^2+144x

6x^3−60x^2+144x

=6x(x−4)(x−6)

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Step-by-step explanation:

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Solve the linear system using substitution
levacccp [35]
Hello there!

3x - y = 3
-x + y = 3

We need to solve 3x - y = 3 for y

Let start by adding -3x to both sides

3x - y = 3

3x - 3x - y = 3 - 3x

-y = 3 - 3x
We cannot leave the variable with a negative sign. We must multiply both sides by -1

-y * -1= (3 - 3x)-1

y = 3x - 3

Substitute 3x -3 for y in -x+y=3

-x + y = 3

-x + 3x - 3 = 3

2x - 3 = 3

2x = 3 + 3

2x = 6

x = 6/2

x = 3

Now substitute 3 for x in y=3x -3

y = 3x - 3

y = 3(3) - 3

y= 9 - 3

y= 6

Thus,

The answer is x=3 and y=6

It is always my pleasure to help students like you :)

As always, I am here to help!


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