102 Amelia is conducting an experiment to determine the effect of ultraviolet light growth of sunflowers

A comet is cruising through the solar system at a speed of 50,000 kilometers per hour foe 4 hours time. What is the total distan

Triss [41]

Answer:

<em>The distance covered by comet is </em> $200,000 km$

Explanation:

Speed is defined as the rate of change of distance with time. It is given by the equation speed= $\bold{\frac{distance}{time}}$

Thus distance= $speed*time$

In this problem it is given that speed of comet= $\frac{50,000km}{hr}$

time travelled by the comet= 4 hours

Thus distance= $speed*time$

= $500000*4$

= $\bold{200,000km}$

5 0

3 years ago

Why would north america will not be able to view the eclipse

Flauer [41]

The North America will not be able to view the eclipse because of its location on the earth caused by the tilting of the earth.

<h3>Effect of tilting of the Earth</h3>

The tilt of the Earth is what causes seasons to occur. These are the seasons in relation to the Northern Hemisphere.

The tilting of the Earth causes the difference in the amount of sun reaching each region of the earth like in the North America continent.

Thus, the North America will not be able to view the eclipse because of its location on the earth caused by the tilting of the earth.

Learn more about eclipse here: brainly.com/question/8643

#SPJ1

4 0

2 years ago

A long, rigid conductor, lying along the x-axis, carries a current of 7.0 A in the negative direction. A magnetic field B is pre

Alisiya [41]

Answer:

0.546 $\hat k$

Explanation:

From the given information:

The force on a given current-carrying conductor is:

$F = I ( \L \limits ^ {\to } \times B ^{\to})\\ \\ dF = I(dL\limits ^ {\to } \times B ^{\to})$

where the length usually in negative (x) direction can be computed as

$\L ^ {\to } = -x\hat i \\dL\limits ^ {\to }- dx\hat i$

Now, taking the integral of the force between x = 1.0 m and x = 3.0 m to get the value of the force, we have:

$\int dF = \int ^3_1 I ( dL^{\to} \times B ^{\to})$

$F = I \int^3_1 ( -dx \hat i ) \times ( 4.0 \hat i + 9.0 \ x^2 \hat j)$

$F = I \int^3_1 - 9.0x^2 \ dx \hat k$

$F = I (9.0) \bigg [\dfrac{x^3}{3} \bigg ] ^3_1 \hat k$

$F = I (9.0) \bigg [\dfrac{3^3}{3} - \dfrac{1^3}{3} \bigg ] \hat k$

where;

current I = 7.0 A

$F = (7.0 \ A) (9.0) \bigg [\dfrac{27}{3} - \dfrac{1}{3} \bigg ] \hat k$

$F = (7.0 \ A) (9.0) \bigg [\dfrac{26}{3} \bigg ] \hat k$

F = 546 × 10⁻³ T/mT $\hat k$

F = 0.546 $\hat k$

4 0

3 years ago

What sort of trade off do you think engineers make between functionality safety and aesthetic when building a real bridge

saul85 [17]

A good engineer will create an outline that meets the useful necessities of the venture and after that play out an anxiety examination to get certainty that the tower will be sheltered under the normal scope of working conditions. By then, the outline will be tastefully satisfying to engineers. On the off chance that the customer needs something all the more stylishly cleaned, he may need to utilize a plan authority. A designer who puts feel initially is taking a chance with his expert standing.

6 0

3 years ago

In which position is it winter in North America? *

Dominik [7]

Answer:

position 4

Explanation:

if the north is tilted away it gets no sunlight, so its winter

6 0

3 years ago

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