Answer:
147.7 N
221.55 Nm
Explanation:
P = Pressure = 100000 Pa
= Mass-specific gas constant = 287.015 J/kg k
T = Temperature = 10+273 = 283 K
C = Drag coefficient = 1.1
A = Area
r = Radius = 0.2 m
v = Speed of wind = 
L = Length of pole
Density
Drag force
Force on the circular sign is 147.7 N
Bending moment at the bottom of the pole is 221.55 Nm
Answer:
F = 614913.88 N
Explanation:
We are given;
Mass of pile driver; m = 1800 kg
Height of fall of pole driver; h = 4.6 m
Depth driven into beam; d = 13.6 cm = 0.136 m
Now, from energy equations and applying to this question, we can write that;
Workdone = Change in potential energy
Formula for workdone is; W = F × d
While the average potential energy here is; W = mg(h + d)
Thus;
Fd = mg(h + d)
Where F is the average force exerted by the beam on the pile driver while in bringing it to rest.
Making F the subject, we have;
F = mg(h + d)/d
F = 1800 × 9.81 × (4.6 + 0.136)/0.136
F = 614913.88 N
Answer:
Basic kinematics, negating drag and assuming ideal conditions, we use the equation:
d=vi*t+1/2*a*t^2
Since vi is 0 (we know this because you’re dropping it, not throwing it)…
…and the only acceleration acting on it is gravity, a=9.8 m/s^2…
…we get
d=1/2(9.8)(5)^2
Explanation:
Some quick mental math tells us that this is about 125 m.
Plugging it in, we find it to be 122.5 m.
Answer:
its false
Explanation:
because if an leaf floats down from a tree it is not considered an object for a free-fall
