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tatyana61 [14]
3 years ago
15

The sides of a square are all increased by 2 in. The area of the new square is 49 in.^2 . What is the length of a side of the or

iginal square?
2 in.
4.5 in.
5 in.
9 in.
Mathematics
2 answers:
dem82 [27]3 years ago
6 0

Answer:

5

Step-by-step explanation:

square root is 49 is 7

so

1 side is 7

so

original side is 7 - 2

which is

5

Licemer1 [7]3 years ago
3 0

Answer:

The original side length was 5 in.

Step-by-step explanation:

Area of new square is (side length)^2.  Here,

that area is (x + 2)^2 = 49 in^2, and we must find x.

Taking the square root of both sides, we get:

x + 2 = +√49 = +7

Subtracting 2 from both sides yields x = -2 + 7 or x = 5

Check:  does (5 + 2)^2 = 49?  YES

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You believe the population is normally distributed. Find the 80% confidence interval. Enter your answer as an open-interval (i.e
victus00 [196]

You intend to estimate a population mean μ from the following sample. 26.2 27.7 8.6 3.8 11.6 You believe the population is normally distributed. Find the 80% confidence interval.  Enter your answer as an open-interval (i.e., parentheses) accurate to twp decimal places.

Answer:

The  Confidence interval = (8.98 , 22.18)

Step-by-step explanation:

From the given information:

mean = \dfrac{ 26.2+ 27.7+ 8.6+ 3.8 +11.6 }{5}

mean = 15.58

the standard deviation \sigma = \sqrt{\dfrac{\sum(x_i - \mu)^2 }{n}}

the standard deviation = \sqrt{\dfrac{(26.2  - 15.58)^2 +(27.7 - 15.58)^2 +(8.6  - 15.58)^2 + (3.8  - 15.58)^2  + (11.6  - 15.58)^2  }{5 }  }

standard deviation = 9.62297

Degrees of freedom df = n-1

Degrees of freedom df = 5 - 1

Degrees of freedom df = 4

For df  at 4 and 80% confidence level, the critical value t from t table  = 1.533

The Margin of Error M.O.E = t \times \dfrac{\sigma}{\sqrt{n}}

The Margin of Error M.O.E = 1.533 \times \dfrac{9.62297}{\sqrt{5}}

The Margin of Error M.O.E = 1.533 \times 4.3035

The Margin of Error M.O.E = 6.60

The  Confidence interval = ( \mu  \pm M.O.E )

The  Confidence interval = ( \mu  +  M.O.E , \mu - M.O.E )

The  Confidence interval = ( 15.58 - 6.60 , 15.58 + 6.60)

The  Confidence interval = (8.98 , 22.18)

7 0
3 years ago
a teacher is experimenting with computer- based instruction. In which situation could the teacher use a hypothesis test for a di
Ilia_Sergeevich [38]

Answer:

(i) She gives each student a pretest. Then she teaches a lesson using a computer program. Afterwards, she gives each student a posttest. The teacher wants to see if the difference in scores will show an improvement.

Step-by- Step

The situation is a case of matched or paired samples since the samples are dependent. The two measurements are drawn from the same pair of individuals The parameter that is tested using matched pairs is the population mean and this is what teacher intends to use a hypothesis test for.

8 0
3 years ago
Pleas help me alot of points​
alekssr [168]

Answer:

12

Step-by-step explanation:

its a square all sides of the square are the same so 48 divided by 4 is 12

5 points is not a lot of points

6 0
3 years ago
How do I solve 6=1/2z
ahrayia [7]

Answer:

z=12

Step-by-step explanation:

divide by 1/2 to get the variable z by itself

3 0
3 years ago
Meredith invested $5,500 into an account that earned 5% interest per year. When she cashed out the investment to use it as a dow
Andrej [43]

Answer:  B. 7739.05=5500(1.05)^t

Step-by-step explanation:

The formula to find the compound amount (compounded yearly):-

A=P(1+r)^t, where P is the principal amount invested,  is the rate of interest and t is time period.

As per given , we have

P=$5500    ,  r=5% = 0.05   and A =  $7,739.05.

Substitute all the values in the formula , we get

7739.05=5500(1+0.05)^t

7739.05=5500(1.05)^t

Hence, the equation describes Meredith's investment based on t, the number of years she kept the account open : 7739.05=5500(1.05)^t

5 0
2 years ago
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