Answer: option d
Explanation:
Project teams must be proactive. Each member of the team should empowered and each member can share ideas and experience in order to make the WBS more precise.
Answer:
Explanation:
Firstly of all we have to construct the min-heap of the k-sub list and each sub list which is a node in the constructed min-heap.
We have several steps to follows:
Step-1. When we compare the two sub lists, at the starting we can compare their first elements which is actually their minimum elements.
Step-2. The min-heap formation will cost be O(k) time.
Step-3. After the step 1 & step 2 we can run the minimum algorithm which can be extracted from the minimum element in the root list.
Step-4. Then Update the root list in the heap and after that simplify the min-heap as maintained by the new minimum element in the root list.
Step-5. If any root sub-list becomes empty in the step 4 then we can take any leaf sub-list from the root and simplify it.
Step-6. At every Extraction of the element it can take up to O(log k) time.
Hence, We can say that the extract of n element in the total whose
Running time will be O(n log k + k) which can be equal to the O(n log k+ k) (since k < n).
First, we have to know the reaction between HCl and Zn. This is a single replacement reaction as shown below:
2 HCl + Zn → ZnCl₂ + 2 H⁺
The molar mass for zinc is 65.38 g/mol. Convert mass to moles and compute for moles of HCl needed to completely react.
Mole of Zn = 1.4 g * 1 mol/65.38 g = 0.0214 moles Zn
Moles of HCl reacted = 0.0214 mol Zn * ( 2 mol HCl/1 mol Zn) = 0.0428 mol
Moles HCl remaining = 0.12 - 0.0428 = 0/077 moles HCl
Answer : The mass of arsenic present in 5.0 g of orpiment is, 1.5 grams.
Explanation : Given,
Mass of orpiment = 5.0 g
As we know that the molar mass of 
is, 246.02 g/mol and the molar mass of As is, 75 g/mol.
As per the question, we conclude that:
As, 246.02 g of contains mass of arsenic = 75 g
So, 5.0 g of contains mass of arsenic = 
Thus, the mass of arsenic present in 5.0 g of orpiment is, 1.5 grams.
