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Crank
2 years ago
10

Another word for oxidation is Decaying Rusting Cutting Burning

Chemistry
2 answers:
anyanavicka [17]2 years ago
7 0
I believe that the answer is A. Decaying
Tasya [4]2 years ago
5 0
The answer would be decaying, however if the oxidation is towards a metal agent, the answer would be rusting.
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What is “monomer” mean?
oksano4ka [1.4K]

it is a molecule* that can be joined with other molecules that are identical to form a polymer*

key words :

a molecule:

a group of atoms bonded together, representing the smallest fundamental unit of a chemical compound that can take part in a chemical reaction.

a polymer:

a substance that has a molecular structure consisting chiefly or entirely of a large number of similar units bonded together

hope this helped, good luck in future studies !

-A

5 0
3 years ago
If a nanometer is one billionth of a meter (0.000 000 00 1 m), how many nanometers are there in one meter?
Anit [1.1K]

Answer:

One billion

Explanation:

A nanometer is a BILLIONTH of a meter which means it takes one billion to equal a meter

6 0
3 years ago
When a 12.8 g sample of KCL dissolves in 75.0 g of water in a calorimeter the temp. drops from 31 Celsius to 21.6 Celsius. Calcu
Delicious77 [7]

Answer:

Step 1: Calculate qsur (the surrounding is

usually the water)

qsur = ? J

m = 75.0 g water

c = 4.184 J/g

oC

ΔT = (Tfinal- Tinitial)= (21.6 – 31.0) = -9.4 oC

qsur = m · c · (ΔT)

qsur = (75.0g) (4.184 J/g

oC) (-9.4 oC)

qsur = - 2949.72 J

First, using the information we know that we

must solve for qsur, which is the water. We know

the mass for water, 75.0g, the specific heat of

the water, 4.184 j/g

o

c, and the change in

temperature, 21.6-31.0 = -9.4 oC. Plugging it

into the equation, we solve for qsur.

Step 2: Calculate qsys qsys = - (qsur)

qsys = - (- 2949.72 J)

qsys = + 2949.72

In this case, the qsur is negative, which means

that the water lost energy. Where did it go? It

went to the system. Thus, the energy of the

system is negative, opposite, the energy of the

surrounding.

Step 3: Calculate moles of the substance

that is the system

Given: 12.8 g KCl

Mol system = (g system given)

(molar mass of system)

Mol system = (12.8 g KCl)

(39.10g + 35.45g)

Mol system = 12.8 g KCl

74.55 g

Mol system = 0.172

Here, we solve for the mol in the system by

using the molar mass of the material in the

system.

Step 4: Calculate ΔH ΔH = q sys .

Mol system

ΔH= + 2949.72 J

0.172 mol

ΔH= +17179.81 J/mol or +1.72 x 104

J/mol

i hope this helps

7 0
3 years ago
WILL GIVE BRAINLIEST <br> Explain why HS2 has a bent geometry, while BeH2 has a linear geometry.
Natali5045456 [20]

Answer:

H2S has a bent geometry, while BeH2 has a linear geometry because: presence of lone pair in H2S

Absence of Lone pair in BeH2

Explanation:

<u>Structure of H2S :</u>

Atomic number of S = 16 = 1s(2 )2s(2) 2p(6) <u>3s(2 )3p(4)</u>

Outer most shell has 6 electron

Valence electron (Involved in bonding) = 6

Out of these  6 electrons ,

2 electrons are formed in bonding with Hydrogen

Rest 4  are non- bonding  and present as lone - pair

H2S exist - sp3 hybridisation

There are 2-Lone pair on S in H2S (look at the image attached)

<u>Structure of H2S :</u>

Atomic number of Be = 4 = 1s(2 ) 2s(2)

Valence electron (Involved in bonding) = 2

These 2- electron  are involved in bonding with two Hydrogen and form liner shape.*Form sp - hybridized

Hence shape is linear because it has non - lone pair.

VSEPR : <u><em>According to this theory lone pair causes repulsion to the bond and cause unstability in the molecule.</em></u>

<u><em>Hence the bonds shifts away from lone pairs . This is why H-S bonds in H2S  shifts way from lone pair</em></u>

5 0
3 years ago
An ionic bond involves _____.A. an attraction between ions of opposite chargeB. water avoidanceC. the sharing of a single pair o
allochka39001 [22]

Answer: D i think

Explanation: Im sorry if it is wrong lol!! I pretty sure thats the answer...

8 0
3 years ago
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