Answer:
23.8 L
Explanation:
There is some info missing. I think this is the original question.
<em>Calculate the volume in liters of a 0.0380M potassium iodide solution that contains 150 g of potassium iodide. Be sure your answer has the correct number of significant digits.</em>
<em />
The molar mass of potassium iodide is 166.00 g/mol. The moles corresponding to 150 grams are:
150 g × (1 mol/166.00 g) = 0.904 mol
0.904 moles of potassium iodide are contained in an unknown volume of a 0.0380 mol/L potassium iodide solution. The volume is:
0.904 mol × (1 L/0.0380 mol) = 23.8 L
Answer:
The mole and atonmicity of both the gases are different, the number of atoms is not same.
Explanation:
The number of atoms in a molecule (compound) depends on mole number and atomicity.
↬ Mole of 100 g H₂ = 100g ÷ 2u = 50 mole
∴Number of atoms in 100 g H₂
= 2 x 50 x 6.022 × 10²³
= 6.022 x 10²⁴ atoms
↬ Mole of 100 g He = 100g ÷ 4u = 25 mole
∴ Number of atoms in 100 g He
= 1 × 25 × 6.022 × 10²³
= 150.55 × 10²³
= 1.5055 x 10²⁵ atoms
Thus, The mole and atonmicity of both the gases are different, the number of atoms is not same.
<u>-TheUnknownScientist</u><u> 72</u>
Answer:
15.7g
Explanation:
mass percent=mass of element/mass of compound *100
39.34=unknown(x)/40g×100
39.34=5x/2
multiplying both sides by 2,we get
5x=78.68
devide by 5 on both sides
x=15.74g Na
Answer:
The temperature for ![\Delta G^o=0[/tex is [tex]T=328.6 K](https://tex.z-dn.net/?f=%5CDelta%20G%5Eo%3D0%5B%2Ftex%20is%20%5Btex%5DT%3D328.6%20K)
Explanation:
The three thermodinamic properties (enthalpy, entropy and Gibbs's energy) are linked in the following formula:
Where:
is Gibbs's energy in kJ
is the enthalpy in kJ
is the entropy in kJ/K
is the temperature in K
Solving:
For 
:
Explanation:
number of moles = number of particle/ 6.02X10^23
= 12.044 X 10^24/6.02×10^23
=20.0066 moles so round it up to 3 S.F
So
=20.0moles
