Answer:
The minimum speed is 14.53 m/s.
Explanation:
Given that,
r = 11 m
Friction coefficient = 0.51
Suppose we need to find the minimum speed, that the cylinder must make a person move at to ensure they will stick to the wall
When frictional force becomes equal to or greater than the weight of person
Then, he sticks to the wall
We need to calculate the minimum speed
Using formula for speed

Where,


Put the value into the formula


Hence, The minimum speed is 14.53 m/s.
The frequency of note C3 is 131
.
<u>Explanation:</u>
Frequency is the measure of repetition of same thing a certain number of times. So frequency is inversely proportional to the wavelength. As wavelength is distance between two successive crests or troughs in a sound wave.
And frequency is the completion of number of cycles in a given time in sound waves. The frequency and wavelength are inversely proportional to each other with velocity of sound being the proportionality constant.
Thus, here the speed of sound is given as 343 m/s, the wavelength of the note is also given as 2.62 m, then frequency will be as follows:

Thus,

So the frequency of note C3 is 131
.
Answer:
W = M g = 150 kg * 9.81 m/s^2 = 1470 N
You were only given 3 significant figures in the question.
During the "U" part of the turn, the car would follow an approximately circular path, and if it's moving at a constant speed, it would have to accelerate toward the center of the circle in order to change its direction.