4 years ago

What factor determines how long a star lives?

Physics

2 answers:

Makovka662 [10]4 years ago

8 0

Their lifespan is determined by how large they are and their weight.

german4 years ago

5 0

The factor that determines how long a star can live is the mass of the star, or how big the star is.

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To check if a stovetop is hot, you place you hand near the top of the stove and feel that it is warm without touching it. You ca

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B.Radiation, Because the heat is Radiating of of the burner. xD

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3 years ago

A net force of 100 n is moving a mass with an acceleration of 5 m/s2. what is the mass of the object? 0.05 kg 20 kg 95 kg 500 kg

dezoksy [38]

F = ma
100n = m(5m/s^2)
100/5 = 20

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4 years ago

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What must be the normal force acting on a crate as it slides across a horizontal floor if the friction acting on the box is 0.49

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Explanation:

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4 years ago

What happens when a spinning ice skater draws in her outstretched arms? Group of answer choices Her moment of inertia increases

kotegsom [21]

Answer:

Her moment of inertia decreases causing her spin to speed up. The physics law behind this phenomenon is the conservation of angular momentum.

Explanation:

<em>Theory</em>

<u>The Law of conservation of angular momentum</u>

The angular momentum of a rotating body or a system remains constant unless it is acted upon by an external unbalance force.

Angular momentum = moment of inertia × angular velocity

The moment of inertia = mass×[perpendicular distance from axis of rotation]²

___________________________________________________________

⇒When skater draws in her outstretched arms the mass distribution get concentrated towards the axis of rotation so the moment of inertia of the body decrease.

But angular moment should conserve so angular velocity increases (spin increases)

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3 years ago

If the coefficient of static friction between your coffee cup and the horizontal dashboard of your car is µs = 0.800, how fast c

Cloud [144]

Answer:

Before start of slide velocity will be 14.81 m/sec

Explanation:

We have given coefficient of static friction $\mu =0.8$

Angle of inclination is equal to $\Theta =tan^{-1}\mu$

$\Theta =tan^{-1}0.8=38.65^{\circ}$

$tan{38.65^{\circ}}=0.8$

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Acceleration due to gravity $g=9.8m/sec^2$

We know that $tan\Theta =\frac{v^2}{rg}$

$0.8=\frac{v^2}{28\times 9.8}$

$v^2=219.52$

$v=14.816m/sec$

So before start of slide velocity will be 14.81 m/sec

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3 years ago