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KIM [24]
3 years ago
13

The concept of plate tectonics regards the earth's ___ as broken into a number of ___ that are in motion relative to each other.

Physics
1 answer:
lord [1]3 years ago
3 0
<span>The concept of plate tectonics regards the earth's CRUST as broken into a number of TECTONIC PLATES that are in motion relative to each other</span>
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A lamp hangs vertically from a cord in a descending elevator that decelerates at 1.4 m/s2. (a) If the tension in the cord is 91
yanalaym [24]

Answer:8.125 kg

Explanation:

Given

deceleration of elevator a=1.4\ m/s^2

suppose T is the tension in the cord

therefore net force on lamp is

F_{net}=T-mg

F_{net}=ma

direction of a and g is in the same direction

T-mg=m(1.4)

T=m(g+a)

m=\dfrac{T}{g+a}

m=\dfrac{91}{9.8+1.4}

m=8.125\ kg

6 0
3 years ago
Describe how a planet, solar system, galaxy, and the universe are related in terms of size.
Alexus [3.1K]

- The Solar System contains the sun and objects that orbit it, including the eight planets, comets, and asteroids, and the Galaxy contains about 100 billion stars, of which the sun is one, as well as large clouds of gas and dust. - The universe contains all physical matter and energy

So Therefore Universe Is the biggest terms of size because it contains all physical matter and energy hope it helps

7 0
3 years ago
Anyone.... help with this two questions...​
PSYCHO15rus [73]

Answer:

what is the question

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Explanation:

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7 0
3 years ago
Read 2 more answers
Jerry runs 60 meters east and then 20 meters west in 10
liraira [26]

Answer: 8 meters per second

Explanation: If you add 60 to 20 you get 80 meters and since he ran those 80 meters in 10 seconds you divide 80 by ten and get 8 and then you get 8m/s

4 0
3 years ago
A 1-oz bullet is traveling with a velocity of 1400 ft/s when it impacts and becomes embedded in a 5-lb wooden block. The block c
schepotkina [342]

   After impact velocity = 14.968 ft/s

Weight and mass of Bullet and wooden block:

Bullet: w = 1oz = 1/16 lb m = 0.001941 lb

wooden block : W = 5lb M = 0.15528 lb

velocity of block and bullet immediately after impact:

Σmv1 + ΣImp = mv2

Resolving vertical component

( m× v₀cos30⁰) + 0 = ( m+M) v'

v' = ( m× v₀cos30⁰)/ (m+M)

v' = 14.968 ft/s

Horizontal and vertical component of the impulse exerted by block on the bullet:

   Here we will apply the principle of impulse and momentum.

 Horizontal component:

          -mv₀ cos30⁰ + RxΔt  =0

                                 RxΔt = mv₀sin30⁰

                                          = 0.001941 × 1400sin30⁰

                                   RxΔt = 1.3587 lb.s

         Vertical component:

                           -mv₀cos30⁰  + RyΔt =  -mv'

                                     RyΔt = m( v₀cos30⁰-v')

                                     RyΔt = 0.001941(1400cos30⁰ - 14.968)

                                              = 2.32 lb.s

     Learn more about impact here:

            brainly.com/question/15008937

                  #SPJ4  

8 0
1 year ago
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