Answer:
the correct answer is torsional
Explanation:
The reactions of the citric acid cycle that provide reducing power for the electron‑transport chain are as follows:
- Conversion of isocitrate to α-ketoglutarate
- Conversion of succinate to fumarate
- Conversion of α-ketoglutarate to succinyl-coA
<h3>
What is citric acid cycle?</h3>
Citric acid cycle also known as kreb cycle is a series of biochemical reactions that involves the synthesis of reduced electron carrier and ATP.
The following steps in the citric acid cycle involves the provision of reducing power for the electron‑transport chain:
- Conversion of isocitrate to α-ketoglutarate: Isocitrate is converted to α-ketoglutarate as catalyzed by isocitrate dehydrogenase.
- Conversion of α-ketoglutarate to succinyl-coA: α-ketoglutarate is converted to succinyl-coA as catalyzed by α-ketoglutarate dehydrogenase.
Learn more about citric acid cycle: brainly.com/question/11459709
Answer:
The flux of the electric field is 677.6 Nm²/C
Explanation:
Given that,
Area = 18 cm²
Charge = 6.0 nC
We need to calculate the flux of the electric field
Using Gauss's law

Where, q = charge
=permittivity of free space
Put the value into the formula


Hence, The flux of the electric field is 677.6 Nm²/C.
Answer:
time is 0.42 sec
Explanation:
Given data
radius = 23 m
angular acceleration = 5.7 rad/s²
to find out
time
solution
we know that radius is constant so that
tangential acceleration At = angular acceleration × radius ............. 1
tangential acceleration = 5.7 × 23 = 131.1 m/s²
and
radial acceleration Ar = (angular velocity)² × radius ........................2
we consider angular velocity = ω
this is acting toward center
so
compare 1 and 2
At = Ar
5.7 r =ω³ r
ω = √5.7 = 2.38746 rad/s
so
ω = 5.7 t
2.387 = 5.7 t
t = 2.387 / 5.7
t = 0.4187
time is 0.42 sec
Answer:
56 m/s
Explanation:
The time we are considering is
t = 15 s
The vertical velocity of the projectile is given by

where
is the initial vertical velocity
is the acceleration due to gravity
Substituting t=15 s, we find the vertical velocity of the projectile at that time:

where the negative sign means the direction is now downward.
The horizontal velocity does not change since there are no forces acting along that direction, so it remains constant:

So, the magnitude of the velocity at the moment of impact is
