Answer:
frequency = 5.52 * 10² Hz
Explanation:
the equation that relates velocity, frequency and wavelength is:
velocity = frequency * wavelength
We are given that:
velocity = 331 m/sec
wavelength = 0.6 m
Substitute with the givens in the equation to get the frequency as follows:
velocity = frequency * wavelength
331 = frequency * 0.6
frequency = 331 / 0.6
frequency = 5.52 * 10² Hz
Hope this helps :)
The cloud of interstellar dust and gas that forms a star is known as a nebula. With an average surface temperature of about 737K, venus is the hottest planet. Hope this helps, and sorry your question didn't get answered in time.
The answers to these questions are:
1. <span>When an individual suffers from anxiety severe enough to DISRUPT HIS DAILY LIFE, he might be suffering from an anxiety disorder.
2. 19 MILLION </span><span>people in the United States suffer from anxiety disorders.
3. I</span><span>f a patient complains that whenever he has to get on a plane he begins to sweat, have chest pain, and nausea, he is most likely suffering from PANIC DISORDER.
4. THAT IT RUNS IN FAMILIES. A lot of researchers and medical professionals believe that anxiety may be hereditary.
</span><span>
5. ANXIETY </span><span>is a state of intense apprehension, uncertainty, and fear resulting from the anticipation of a threatening event or situation.
6. </span><span>A twin is MORE likely to suffer from an anxiety disorder if the other twin has some form of anxiety disorder.
7. </span><span>Generalized Anxiety Disorder (GAD) is characterized by PROLONGED AND EXCESSIVE WORRY EVEN WHEN THERE IS NO APPARENT CAUSE FOR CONCERN.
8. </span><span>Specific Phobia is characterized by EXAGGERATED OR IRRATIONAL FEAR OF OBJECTS OR SITUATIONS THAT ARE NOT GENERALLY HARMFUL.
9. </span>Post-Traumatic Stress Disorder (PTSD) is characterized by <span>FLASHBACKS OR NIGHTMARES.
10. </span>Obsessive-Compulsive Disorder is characterized by OBSESSIVE, IRRATIONAL THOUGHTS THAT INCREASE/INTENSIFY FEELINGS OF ANXIETY.
These answers are based from what I understand from various sources. Hope this helps. :)
If he dropped them both at the same time, then as close as anyone could tell, they both hit the ground at the same time.
Since the ladder is standing, we know that the coefficient
of friction is at least something. This [gotta be at least this] friction
coefficient can be calculated. As the man begins to climb the ladder, the
friction can even be less than the free-standing friction coefficient. However,
as the man climbs the ladder, more and more friction is required. Since he
eventually slips, we know that friction is less than what's required at the top
of the ladder.
The only "answer" to this problem is putting lower
and upper bounds on the coefficient. For the lower one, find how much friction
the ladder needs to stand by itself. For the most that friction could be, find
what friction is when the man reaches the top of the ladder.
Ff = uN1
Fx = 0 = Ff + N2
Fy = 0 = N1 – 400 – 864
N1 = 1264 N
Torque balance
T = 0 = N2(12)sin(60) – 400(6)cos(60) – 864(7.8)cos(60)
N2 = 439 N
Ff = 439= u N1
U = 440 / 1264 = 0.3481
