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Evgesh-ka [11]
3 years ago
11

In tests on earth a lunar surface exploration vehicle (mass = 5.57 × 103 kg) achieves a forward acceleration of 0.207 m/s2. to a

chieve this same acceleration on the moon, the vehicle's engines must produce a drive force of 1.60 × 103 n. what is the magnitude of the frictional force that acts on the vehicle on the moon?
Physics
1 answer:
spayn [35]3 years ago
5 0
The answer is 9000         or b                          
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The diver on the diving board is 10 meters high and has a mass of 0.050kg, what is his GPE?
sveta [45]

Answer:

<h2>4.9 J</h2>

Explanation:

The gravitational potential energy of a body can be found by using the formula

GPE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 9.8 m/s²

From the question we have

GPE = 10 × 9.8 × 0.05

We have the final answer as

<h3>4.9 J</h3>

Hope this helps you

6 0
3 years ago
There is a clever kitchen gadget for drying lettuce leaves after you wash them. It consists of a cylindrical container mounted s
Maslowich

Answer:

.a = 849.05 m / s²

Explanation

The centripetal acceleration is

            a = v² / r

     

Linear and angular velocity are related

          v = w r

Angular velocity and frequency are related by

        w = 2π f

Let's replace

        a = w² r

         a = 4π² f² r

Let's reduce to the SI system

       f = 2.30 rev / s (2π rad / 1 rev) = 14.45 rad / s

       .r = 10.3 cm = 0.103 m

Let's calculate

       a = 4π² 14.45²  0.103

       .a = 849.05 m / s²

8 0
3 years ago
In 1970, a rocket powered car called Blue Flame achieved a maximum speed of 1.00(10 km/h (278m/s).Suppose the magnitude of the c
sammy [17]

Answer:

Distance traveled during this acceleration will be 6950 m

Explanation:

Wear have given maximum speed tat will be equal to final speed of the car        v = 278 m/sec

Constant acceleration a=5.56m/sec^2

As the car starts initially starts from rest so initial velocity of the car u = 0 m/sec

From third equation of motion v^2=u^2+2as

Putting all values in equation

278^2=0^2+2\times 5.56\times s

s = 6950 m

So distance traveled during this acceleration will be 6950 m

3 0
3 years ago
Explain why the same side of the moon is always facing Earth.
Ad libitum [116K]

Answer:

The moon keeps the same face pointing towards the Earth because its rate of spin is tidally locked so that it is synchronized with its rate of revolution (the time needed to complete one orbit). In other words, the moon rotates exactly once every time it circles the Earth.

7 0
3 years ago
Calculate the speed of an 8.0x10^4 kg airliner with a kinetic energy of 1.1x10^9 j ...?
Over [174]
Kinetic energy is the energy possessed by an object on motion. it is expressed as follows:

KE = 0.5mv^2

where m is the mass and v is the velocity of the object. We calculate as follows:


KE = 0.5mv^2
1.1x10^9 J = 0.5(8.0x10^4 kg) v^2
v = 165.83 m/s
6 0
3 years ago
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