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Evgesh-ka [11]
3 years ago
11

In tests on earth a lunar surface exploration vehicle (mass = 5.57 × 103 kg) achieves a forward acceleration of 0.207 m/s2. to a

chieve this same acceleration on the moon, the vehicle's engines must produce a drive force of 1.60 × 103 n. what is the magnitude of the frictional force that acts on the vehicle on the moon?
Physics
1 answer:
spayn [35]3 years ago
5 0
The answer is 9000         or b                          
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An electromagnetic wave with frequency 65.0hz travels in an insulating magnetic material that has dielectric constant 3.64 and r
torisob [31]
Ans: Intensity = I = 5.8 * 10^{-8} W/m^2

Explanation:
First you need to find out the speed of Electromagnetic wave:

Since
v = \sqrt{ \frac{1}{\mu\epsilon} }


v = \sqrt{ \frac{1}{\mu_r\mu_ok\epsilon_o} }
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k = 3.64 \\
\epsilon_o = 8.85 * 10^{-12}

Plug in the values:
v = \sqrt{ \frac{1}{(5.18)(4\pi*10^{-7})(3.64)(8.85*10^{-12})} }
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Now that we have "v", we can use the following formula to find the intensity of wave:

I =  \frac{k\epsilon_o*v*E_{max}^2}{2}

I =  \frac{(3.64)(8.85*10^{-12})
*(6.9*10^7)*(7.20*10^{-3})^2}{2}

Intensity = I = 5.8 * 10^{-8} W/m^2

4 0
3 years ago
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