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3 years ago

What conclusion can she make from her experiment?

Chemistry

2 answers:

slamgirl [31]3 years ago

6 0

Answer:

Im pretty sure the answer is D

Explanation

pishuonlain [190]3 years ago

5 0

Answer:

hii samyy

Explanation:

nice killua profile pic :))

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What is atomic hydrogen?<br>

goldenfox [79]

A hydrogen atom is an atom of the chemical element hydrogen. The electrically neutral atom contains a single positively charged proton and a single negatively charged electron bound to the nucleus by the Coulomb force. Atomic hydrogen constitutes about 75% of the baryonic mass of the universe.

8 0

3 years ago

Read 2 more answers

A reaction in the laboratory yields 5.98 g KAI(SO2)2, How many moles of potassium aluminum

Ivahew [28]

Answer:

0.0308 mol

Explanation:

In order to convert from grams of any given substance to moles, we need to use its molar mass:

Molar mass of KAI(SO₂)₂ = MM of K + MM of Al + (MM of S + 2*MM of O)*2

Molar mass of KAI(SO₂)₂ = 194 g/mol

Now we <u>calculate the number of moles of KAI(SO₂)₂ contained in 5.98 g</u>:

5.98 g ÷ 194 g/mol = 0.0308 mol

6 0

3 years ago

Can someone help me with this

Trava [24]

Answer:

I think cold front if not than its c

7 0

3 years ago

Match the following with their correct molecular weight. 2-butanone Propyl acetate 4-methyl-2-pentanone Butyl acetate Methanol E

Hatshy [7]

Answer:

2-butanone = 72.11 g/mol (option F)

Propyl acetate = 102.13 g/mol (option C)

4-methyl-2-pentanone = 100.16 g/mol (option D)

Butyl acetate = 116.16 g/mol (option B)

Methanol = 32.04 g/mol (option E)

Ethanol = 46.07 g/mol (option A)

Explanation:

Step 1: Data given

Molar mass of C = 12.01 g/mol

Molar mass of H = 1.01 g/mol

Molar mass of O = 16.00 g/mol

Step 2:

2-butanone = C4H8O

⇒ 4*12.01 + 8*1.01 + 16.00 = 72.11 g/mol (option F)

Propyl acetate = C5H10O2

⇒ 5*12.01 + 10*1.01 + 2*16.00 = 102.13 g/mol (option C)

4-methyl-2-pentanone = C6H12O

⇒ 6*12.01 + 12*1.01 + 16.00 = 100.16 g/mol (option D)

Butyl acetate = C6H12O2

⇒ 6*12.01 + 12*1.01 + 2*16.00 = 116.16 g/mol (option B)

Methanol = CH3OH = CH4O

⇒ 12.01 + 4*1.01 + 16.00 = 32.04 g/mol (option E)

Ethanol = C2H5OH = C2H6O

⇒ 2*12.01 + 6*1.01 + 16.00 = 46.07 g/mol (option A)

4 0

3 years ago

For the following reaction, the equilibrium constant Kc is 0.80 at a certain temperature. If the concentration of NO(g) and NOBr

velikii [3]

Answer:

[Br₂] = 1.25M

Explanation:

2NO (g) + Br₂ (g) ⇄ 2NOBr (g)

Eq 0.80M ? 0.80M

That's the situation told, in the statement.

Let's make the expression for Kc

Kc = [NOBr]² / [Br₂] . [NO]²

Kc = 0.80² / [Br₂] . [0.80]²

0.80 = 1 / [Br₂]

[Br₂] = 1 / 0.80 → 1.25

4 0

4 years ago