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lubasha [3.4K]
3 years ago
9

What conclusion can she make from her experiment?

Chemistry
2 answers:
slamgirl [31]3 years ago
6 0

Answer:

Im pretty sure the answer is D

Explanation

pishuonlain [190]3 years ago
5 0

Answer:

hii samyy

Explanation:

nice killua profile pic :))

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SOMEONE PLEASE HELP ME WILL MARK BRAINLIEST PLEASE!!
QveST [7]

O₂ required = 1/2 x 7.8 = 3.9 moles

7 0
3 years ago
What is the condensed electron configuration for nitrogen
Alenkinab [10]

Answer:

In writing the electron configuration for nitrogen the first two electrons will go in the 1s orbital. Since 1s can only hold two electrons the next 2 electrons for N goes in the 2s orbital. The remaining three electrons will go in the 2p orbital. Therefore the N electron configuration will be 1s22s22p3.

Explanation:

hope you get it right:)

6 0
3 years ago
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The molar masses of three gases, A, B, and C, are 4 grams, 16 grams, and 32 grams respectively. Which sentence represents the ef
timurjin [86]
This is where something called Graham's Law applies. Grahams law says that the rate of effusion is inversely proportional to the square root of the molar mass of a gas. What that means is that the less the molar mass of a gas is, the less quickly the gas effuses (effusion being the rate at which a gas can travel through a small hole). A great way to think about this is that effusion is thought about as though the gas is traveling through a small hole, so smaller particles would be able to go through it with greater ease than would a large particle. I don't know what particular sentences the question asks for are, but the answer should be that gas A (molar mass 4) has the greatest effusion rate, gas B (molar mass 16) has the second fastest effusion rate, and gas C (molar mass 32) has the slowest effusion rate.
3 0
4 years ago
Read 2 more answers
A useful application of oxalic acid is the removal of rust (fe2o3) from, say, bathtub rings according to the reaction below. fe2
Butoxors [25]

Answer: 170.9 g


Explanation:



1) Balanced chemical equation:


Fe₂O₃(s) + 6 H₂C₂O₄ (aq) → 2Fe(C₂O₄)₃³⁻ + 3H₂O + 6H⁺(aq)


2) mole ratio:


1mol Fe₂O₃ : 6 mol H₂C₂O₄


3) number of moles of H₂C₂O₄ in the solution


M = n / V ⇒ n = MV = 0.800M × 0.800 liter = 6.40 moles


4) Porportionality


1mol Fe₂O₃ / 6 mol H₂C₂O₄ = x / 6.40 mol H₂C₂O₄


⇒ x = 1.07 mol Fe₂O₃


5) Convert 1.07 mol Fe₂O₃ to grams.


molar mass Fe₂O₃ = 159.69 g/mol


mass in grams = molaer mass × number of moles


mass in grams = 159.69 g/mol × 1.07 mol = 170.9 g

3 0
3 years ago
2. You have a 2.50 mole gas sample in a 500.0 mL flask at 25.0 °C.
SIZIF [17.4K]

Considering the ideal gas law, the pressure of the gas sample is 122.18 atm.

<h3>What is an ideal gas</h3>

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

<h3>Definition of ideal gas law</h3>

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of gases:

P×V = n×R×T

<h3>Pressure of the gas sample</h3>

In this case, you know:

  • P= ?
  • V= 500 mL= 0.5 L
  • n= 2.50 moles
  • R= 0.082 \frac{atm L}{mol K}
  • T= 25 °C= 298 K

Replacing in the ideal gas law:

P×0.5 L = 2.50 moles ×0.082 \frac{atm L}{mol K} ×298 K

Solving:

P= (2.50 moles ×0.082 \frac{atm L}{mol K} ×298 K)÷ 0.5 L

<u><em>P= 122.18 atm</em></u>

Finally, the pressure of the gas sample is 122.18 atm.

Learn more about the ideal gas law:

brainly.com/question/4147359

#SPJ1

7 0
2 years ago
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