We can say an atom is electrically neutral if both electron (for electric charge) and proton (for positive charge) have the exact same amount
Since the number are needed in some amount to be considered stable (*2-1st level<span>-need 8 for valence level) , </span><span> The atom that has 7 protons and 7 electrons would be considered enough</span>
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Chemistry => Stoichiometry => Limiting reactant
The maximum number of molecules that can be formed will depend on the limiting reactant. The limiting reactant corresponds to the reactant that produces the least amount of product, or in other words, the one that is completely consumed in the reaction.
To find the limiting reactant we are going to divide the moles of each reactant by the stoichiometric coefficients of the balanced equation, the reactant with the lowest ratio will be the limiting reactant.
The balanced equation for this reaction will be:
We have, according to the image the following number of molecules:
Xe=2molecules
F2=4molecules
The limiting reactant will be:
Both reactants are limiting reactants. We can take any reactant and we will have the same number of molecules of XeF4 formed. The ratio Xe to XeF4 is 1/1, so the molecules of XeF4 that can be formed will be:
Answer: 2 XeF4 molecules
Ionization energy is the energy required to lose an electron and form an ion. The stronger is the attraction of the atom and the electron the higher the ionization energy, and the weaker is the attraction of the atom and the electron the higher the ionization energy. This leads to a clear trend in the periodic table. Given that the larger the atom the weaker the attraction of the atom to the valence electrons, the easier they will be released, and the lower the ionization energy. This is, as you go downward in a group, the ionization energy decreases. So, the element at the top of the group will exhibit the largest ionization energy. <span>Therefore, the answer is that of the four elements of group 7A, fluorine will have the largest first ionization energy.</span>