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wlad13 [49]
3 years ago
14

Calculate the wavelength and frequency of an emitted photon of gamma radiation that has energy of 2.93 × 109 J/mol

Chemistry
1 answer:
shusha [124]3 years ago
6 0

Answer:

Explanation: Calculate the wavelength and frequency of an emitted photon of gamma radiation that has energy of 2.93 × 109 J/mol

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You start out with 800 moles of a radioactive substance. After 24 hours, 100 moles remain. What is the half-life of the substanc
Nookie1986 [14]

The half life of the substance is 8 hours , Option D is the correct answer.

<h3></h3>

What is Half Life ?

Half-life is the time required by an unstable element  to reduce to half of its initial value.

The term is commonly used in nuclear physics.

The formula is

\rm N(t) = \; N_{0} \;(\dfrac{1}{2} )^{\frac{t}{t_{1/2} } }

N(t)     =    quantity of the substance remaining

N ₀      =    initial quantity of the substance

t    =  time elapsed

\rm t_{1/2}    =    half life of the substance

The data given in the question is N ₀ = 800 moles , N(t)= 100 , t= 24 hours

\rm t_{1/2} =\; ?

Substituting values in the equation

\rm 100 = \; 800 \;(\dfrac{1}{2} )^{\frac{24}{t_{1/2} } }

\rm \dfrac{100}{800}  =  \;(\dfrac{1}{2} )^{\frac{24}{t_{1/2} } }\\\\\rm \dfrac{1}{8}  =  \;(\dfrac{1}{2} )^{\frac{24}{t_{1/2} } }\\\\\rm (\dfrac{1}{2})^{3}  =  \;(\dfrac{1}{2} )^{\frac{24}{t_{1/2} } }\\\\\rm 3=\dfrac{24}{t_{1/2} }\\\\t_{1/2}= \dfrac{24}{3}\\\\t_{1/2} = 8 hours

Therefore half life of the substance is 8 hours , Option D is the correct answer.

To know more about Half Life

brainly.com/question/24710827

#SPJ2

3 0
2 years ago
The height of a wave is called its amplitude. From the noises of the mosquito and the air boat, which aspect of sound is related
TEA [102]
The answer is The loudness of sound is related to its amplitude, this is off edmentum exactly so I advise changing up the wording. You can say something about the pitch or you can word it like, The sound of the wave is related to how loud the sound can be. Hope this helped
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¿Cómo funciona un antiácido cuando se consume para aliviar la acidez estomacal y qué nombre recibe esta reacción?
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3 years ago
Which planets have a larger orbital radii, terrestrial planets or gas giants
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5 0
2 years ago
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Complete ionic,net and spectator ions for the following
yawa3891 [41]

Answer:

Explanation:

1) ZnBr₂ (aq) + AgNO₃ (aq)

Chemical equation:

 ZnBr₂ (aq) + AgNO₃ (aq)  →Zn(NO₃)₂(aq) + AgBr(s)

Balanced chemical equation:

ZnBr₂ (aq) + 2AgNO₃ (aq)  →Zn(NO₃)₂(aq) + 2AgBr(s)

Ionic equation:

Zn²⁺(aq) + Br₂²⁻ (aq) + 2Ag⁺ (aq)+ 2NO⁻₃ (aq)  → Zn²⁺(aq) +(NO₃)₂²⁻(aq) + 2AgBr(s)

Net ionic equation:

Br₂²⁻ (aq) + 2Ag⁺ (aq)   →    2AgBr(s)

The Zn²⁺((aq) and NO⁻₃ (aq) are spectator ions that's why these are not written in net ionic equation. The AgBr can not be splitted into ions because it is present in solid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.  

2) Ca(OH)₂ (aq) + Na₂SO₄ (aq)

Chemical equation:

Ca(OH)₂ (aq) + Na₂SO₄ (aq)  →   CaSO₄(s) + NaOH(aq)

Balanced chemical equation:

Ca(OH)₂ (aq) + Na₂SO₄ (aq)  →   CaSO₄(s) + 2NaOH(aq)

Ionic equation:

Ca²⁺(aq)  + OH₂²⁻  (aq) + 2Na⁺(aq) + SO₄²⁻ (aq)  →   CaSO₄(s) + 2Na⁺(aq) + 2OH⁻ (aq)

Net ionic equation:

Ca²⁺(aq)   + SO₄²⁻ (aq)  →   CaSO₄(s)

The OH⁻ ((aq)  and Na⁺ (aq) are spectator ions that's why these are not written in net ionic equation. The CaSO₄ can not be splitted into ions because it is present in solid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.

3) Al(NO₃)₃ (aq) + Na₃PO₄ (aq)

Chemical equation:

 Al(NO₃)₃ (aq) + Na₃PO₄ (aq)   → Al(PO₄)(s) + NaNO₃ (aq)

Balanced chemical equation:

Al(NO₃)₃ (aq) + Na₃PO₄ (aq)   → Al(PO₄)(s) + 3NaNO₃ (aq)

Ionic equation:

Al³⁺(aq) + 3NO⁻₃ (aq) + 3Na⁺(aq) + PO₄³⁻ (aq)   → Al(PO₄)(s) + 3Na⁺(aq) + NO⁻₃ (aq)

Net ionic equation:

Al³⁺(aq) + PO₄³⁻ (aq)   → Al(PO₄)(s)

The Na⁺((aq) and NO⁻₃ (aq) are spectator ions that's why these are not written in net ionic equation. The  Al(PO₄) can not be splitted into ions because it is present in solid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.  

4) FeSO₄ (aq) + Ba(OH)₂ (aq)

Chemical equation:

FeSO₄ (aq) + Ba(OH)₂ (aq)  → BaSO₄(s) + Fe(OH)₂(aq)

The equation is already balanced.

Ionic equation:

Fe²⁺(aq)  + SO₄²⁻ (aq) + Ba²⁺(aq)  + 2OH⁻ (aq)  → BaSO₄(s) + Fe²⁺(aq)  + 2OH⁻(aq)

Net ionic equation:

SO₄²⁻ (aq) + Ba²⁺(aq) → BaSO₄(s)

The Fe²⁺ (aq) and OH⁻ (aq) are spectator ions that's why these are not written in net ionic equation. The  BaSO₄ can not be splitted into ions because it is present in solid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.

8 0
3 years ago
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