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morpeh [17]
2 years ago
8

If it requires 45.8 cal to melt 8.4 g of a substance, what is the heat of

Chemistry
2 answers:
GarryVolchara [31]2 years ago
8 0

384.72 J is the heat of fusion of the substance.

<h3>What is the heat of fusion? </h3>

It is the change in the value of the enthalpy by providing energy i.e. heat, for a specific quantity of the substance.

Given data:

Heat of fusion  =?

Mass of substance = 8.4 g

Unknown:

Amount of energy required to melt the given mass = 45.8 cal

Solution:

To solve this problem, the amount of energy required to melt the substance is given as;

H  = m L

m is the mass

L is the heat of fusion

Insert the given parameters and solve;

H  = 8.4 g  x 45.8 cal = 384.72 J

Hence, 384.72 J is the heat of fusion of the substance.

Learn more about heat of fusion here:

brainly.com/question/19531870

#SPJ2

Tom [10]2 years ago
5 0

Answer:

5.452  cal/g

Explanation:

45.8 cal / 8.4 g =   5.4523  cal/g

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Mixtures of benzene and cyclohexane exhibit ideal behavior. A solution was created containing 1.5 moles of liquid benzene and 2.
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Explanation:

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For the second equation:

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370torr = 0.700P^0_{A}+0.300P^0_{B}<em>(2)</em>

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<em>Vapour pressure of cyclohexane at 50°C is 490torr</em>

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370torr = 0.700*490torr+0.300P^0_{B}

P^0_{B}=90torr

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