Answer:
D
Explanation:
This creates a gap that we call an oceanic trench
:)
Answer:
a.) because your ankle is taking in cold energy from the cold pack
Explanation:
all of the other ones say heat, which is not applied in this question
In an electrolytic cell, the electrode that acts as a source of electrons to the solution is called the <u>cathode</u>; the chemical change that occurs at this electrode is called <u>reduction</u>.
<h3>Define Electrolyte:-</h3>
An electrolyte is a material that separates into charged ions when it is in contact with water. Cations are positively charged ions. Anions are ions that are negatively charged. A substance that may conduct an electric current when melted or dissolved in water is known as an electrolyte.
<h3>Electrochemical cell </h3>
There are three main categories of electrochemical cells. the galvanic cell, the concentration cell, and the electrolytic cell. These cells all share the same four fundamental components. These are the elements
- The electrolyte serves as the conduit for current flow between the anode and the cathode. In an aqueous solution, it normally is homogeneous, but in moist soil, the concentration or kind of dissolved compounds may vary locally.
- The anode, which can conduct electricity and is in contact with the electrolyte, corrodes when it combines with the chemicals in the electrolyte.
- A metal also contacts the electrolyte at the cathode. It is protected from corrosion rather than corroded.
- Anode and cathode are connected by the conductor, which also completes the circuit.
Learn more about Electrochemical cells here:-
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Explanation:
It is known that rate of effusion of gases are inversely proportional to the square root of their molar masses.
And, half of the helium (1.5 L) effused in 24 hour. So, the rate of effusion of He gas is calculated as follows.
= 0.0625 L/hr
As, molar mass of He is 4 g/mol and molar mass of
is 32 g/ mol.
Now,

= 2.83
or, rate of
= 
Rate of
= 0.022 L/hr.
This means that 0.022 L of
gas effuses in 1 hr
So, time taken for the effusion of 1.5 L of
gas is calculated as follows.
= 68.18 hour
Thus, we can conclude that 68.18 hours will it take for half of the oxygen to effuse through the membrane.
By gaining an electron (perhaps via beta particle). The H+ ion needs another electron to remove its positive charge.