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2 years ago

What is the solution set for -4 x - 10 ≤ 2? A. x ≤ -3 B. x ≥ -3 C.x ≤ -3 D. x ≥ 2

Mathematics

2 answers:

andrew-mc [135]2 years ago

8 0

Answer:

The answer to your question is b

Step-by-step explanation:

kramer2 years ago

6 0

Answer:

B. x ≥ -3

Step-by-step explanation:

-4 x - 10 ≤ 2

add ten by both sides

-4x≤12

divide -4 by both sides

x ≤ -3

BUT because you divded you have to switch the sign so

x ≥ -3

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$(x - 4) {}^{2} - 28 = 8 \\ (x - 4) {}^{2} = 8 + 28 \\ (x - 4) {}^{2} = 36$

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$\sqrt{(x - 4) {}^{2} } = ± \sqrt{36} \\x - 4 = ±6 \\ x _{1}- 4 = 6 \: \: \: \: \: \: \: \: \: \: x _{2}- 4 = - 6 \\ x_{1} = 6 + 4 \: \: \: \: \: \: \: \: \: \: x_{2} = - 6 + 4 \\ x_{1} = 10 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x_{2} = - 2$

Well he started off correct to the point of completing the square.

$(x - 3) {}^{2} = 16 \\ x - 3 = ±4 \\ \: x_{1} - 3 = 4 \: \: \: \: \: \: \: \: \: \: \: \: x_{2} - 3 = - 4 \\ x_{1} = 7 \: \: \: \: \: \: \: \: \: \: x_{2} = - 1$

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